2NOBr(g) = 2NO(g) + Br₂(g) Kp = 0.416 The current pressures for the system are given below. What is the reaction quotient, Q, for the system? PNOBY = 0.4488 atm PNO=0.5514 atm PBr₂ = 0.2756 atm Q = [?] Reaction Quotient Enter

Introduction to General, Organic and Biochemistry
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Chapter7: Reaction Rates And Chemical Equilibrium
Section: Chapter Questions
Problem 7.81P
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### Reaction Quotient Calculation for a Gas Phase Equilibrium System

An equilibrium reaction is represented as follows:

\[ 2 \text{NOBr}(g) \rightleftharpoons 2 \text{NO}(g) + \text{Br}_2(g) \]

Given the equilibrium constant \( K_p = 0.416 \), we want to find the reaction quotient, \( Q \), for the system using the current pressures provided.

#### Current Pressures:
- **Pressure of NOBr, \( P_{\text{NOBr}} \)**: 0.4488 atm
- **Pressure of NO, \( P_{\text{NO}} \)**: 0.5514 atm
- **Pressure of Br2, \( P_{\text{Br2}} \)**: 0.2756 atm

The reaction quotient, \( Q \), is calculated using the following formula for the given reaction:

\[ Q = \frac{(P_{\text{NO}})^2 (P_{\text{Br2}})}{(P_{\text{NOBr}})^2} \]

Substitute the given pressures into the equation to find \( Q \).

#### Example Calculation:

1. \( P_{\text{NO}} = 0.5514 \, \text{atm} \)
2. \( P_{\text{Br2}} = 0.2756 \, \text{atm} \)
3. \( P_{\text{NOBr}} = 0.4488 \, \text{atm} \)

\[ Q = \frac{(0.5514)^2 \times 0.2756}{(0.4488)^2} \]

Perform the calculation to determine \( Q \).

An answer box and an "Enter" button are provided for students to input their calculated value of \( Q \) and check if it is correct. 

**Note**: Ensure you perform the calculation accurately with proper units to derive the correct reaction quotient \( Q \).
Transcribed Image Text:### Reaction Quotient Calculation for a Gas Phase Equilibrium System An equilibrium reaction is represented as follows: \[ 2 \text{NOBr}(g) \rightleftharpoons 2 \text{NO}(g) + \text{Br}_2(g) \] Given the equilibrium constant \( K_p = 0.416 \), we want to find the reaction quotient, \( Q \), for the system using the current pressures provided. #### Current Pressures: - **Pressure of NOBr, \( P_{\text{NOBr}} \)**: 0.4488 atm - **Pressure of NO, \( P_{\text{NO}} \)**: 0.5514 atm - **Pressure of Br2, \( P_{\text{Br2}} \)**: 0.2756 atm The reaction quotient, \( Q \), is calculated using the following formula for the given reaction: \[ Q = \frac{(P_{\text{NO}})^2 (P_{\text{Br2}})}{(P_{\text{NOBr}})^2} \] Substitute the given pressures into the equation to find \( Q \). #### Example Calculation: 1. \( P_{\text{NO}} = 0.5514 \, \text{atm} \) 2. \( P_{\text{Br2}} = 0.2756 \, \text{atm} \) 3. \( P_{\text{NOBr}} = 0.4488 \, \text{atm} \) \[ Q = \frac{(0.5514)^2 \times 0.2756}{(0.4488)^2} \] Perform the calculation to determine \( Q \). An answer box and an "Enter" button are provided for students to input their calculated value of \( Q \) and check if it is correct. **Note**: Ensure you perform the calculation accurately with proper units to derive the correct reaction quotient \( Q \).
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