2NOBr(g) = 2NO(g) + Br₂(g) Kp = 0.416 The current pressures for the system are given below. What is the reaction quotient, Q, for the system? PNOBY = 0.4488 atm PNO=0.5514 atm PBr₂ = 0.2756 atm Q = [?] Reaction Quotient Enter
2NOBr(g) = 2NO(g) + Br₂(g) Kp = 0.416 The current pressures for the system are given below. What is the reaction quotient, Q, for the system? PNOBY = 0.4488 atm PNO=0.5514 atm PBr₂ = 0.2756 atm Q = [?] Reaction Quotient Enter
Introduction to General, Organic and Biochemistry
11th Edition
ISBN:9781285869759
Author:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
Publisher:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
Chapter7: Reaction Rates And Chemical Equilibrium
Section: Chapter Questions
Problem 7.81P
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![### Reaction Quotient Calculation for a Gas Phase Equilibrium System
An equilibrium reaction is represented as follows:
\[ 2 \text{NOBr}(g) \rightleftharpoons 2 \text{NO}(g) + \text{Br}_2(g) \]
Given the equilibrium constant \( K_p = 0.416 \), we want to find the reaction quotient, \( Q \), for the system using the current pressures provided.
#### Current Pressures:
- **Pressure of NOBr, \( P_{\text{NOBr}} \)**: 0.4488 atm
- **Pressure of NO, \( P_{\text{NO}} \)**: 0.5514 atm
- **Pressure of Br2, \( P_{\text{Br2}} \)**: 0.2756 atm
The reaction quotient, \( Q \), is calculated using the following formula for the given reaction:
\[ Q = \frac{(P_{\text{NO}})^2 (P_{\text{Br2}})}{(P_{\text{NOBr}})^2} \]
Substitute the given pressures into the equation to find \( Q \).
#### Example Calculation:
1. \( P_{\text{NO}} = 0.5514 \, \text{atm} \)
2. \( P_{\text{Br2}} = 0.2756 \, \text{atm} \)
3. \( P_{\text{NOBr}} = 0.4488 \, \text{atm} \)
\[ Q = \frac{(0.5514)^2 \times 0.2756}{(0.4488)^2} \]
Perform the calculation to determine \( Q \).
An answer box and an "Enter" button are provided for students to input their calculated value of \( Q \) and check if it is correct.
**Note**: Ensure you perform the calculation accurately with proper units to derive the correct reaction quotient \( Q \).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Faf34c8cd-64a3-45bc-a064-10a06ef3c764%2Fcaa0d511-5880-4c68-aa0c-2d0af820ab1c%2F6ga9ybd_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Reaction Quotient Calculation for a Gas Phase Equilibrium System
An equilibrium reaction is represented as follows:
\[ 2 \text{NOBr}(g) \rightleftharpoons 2 \text{NO}(g) + \text{Br}_2(g) \]
Given the equilibrium constant \( K_p = 0.416 \), we want to find the reaction quotient, \( Q \), for the system using the current pressures provided.
#### Current Pressures:
- **Pressure of NOBr, \( P_{\text{NOBr}} \)**: 0.4488 atm
- **Pressure of NO, \( P_{\text{NO}} \)**: 0.5514 atm
- **Pressure of Br2, \( P_{\text{Br2}} \)**: 0.2756 atm
The reaction quotient, \( Q \), is calculated using the following formula for the given reaction:
\[ Q = \frac{(P_{\text{NO}})^2 (P_{\text{Br2}})}{(P_{\text{NOBr}})^2} \]
Substitute the given pressures into the equation to find \( Q \).
#### Example Calculation:
1. \( P_{\text{NO}} = 0.5514 \, \text{atm} \)
2. \( P_{\text{Br2}} = 0.2756 \, \text{atm} \)
3. \( P_{\text{NOBr}} = 0.4488 \, \text{atm} \)
\[ Q = \frac{(0.5514)^2 \times 0.2756}{(0.4488)^2} \]
Perform the calculation to determine \( Q \).
An answer box and an "Enter" button are provided for students to input their calculated value of \( Q \) and check if it is correct.
**Note**: Ensure you perform the calculation accurately with proper units to derive the correct reaction quotient \( Q \).
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