Sodium hydroxide in the amount of 10.0 g is allowed to react with 1.12 L of carbon dioxide gas at STP 2NaOH(s) + CO2(g) => Na2CO3(s) + H2O(g)and the product dried out to permanent weight.What will be the mass of the product? (a) 12.7 g (b) 11.2 g (c) 13.3 g (d) 6.62 g(d) None of those. If so, what is your answer?

At STP :- 1 mol of gass is equal to 22.4 L Number of moles = mass / molar mass

Answered: 2NaOH(s) + CO2(g) => Na2CO3(s) + H2O(g)

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Sodium hydroxide in the amount of 10.0 g is allowed to react with 1.12 L of carbon dioxide gas at STP 2NaOH(s) + CO₂(g) => Na₂CO₃(s) + H₂O(g)
and the product dried out to permanent weight.
What will be the mass of the product?

(a) 12.7 g (b) 11.2 g (c) 13.3 g (d) 6.62 g

(d) None of those. If so, what is your answer?

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