2n+5,3n | in=0 3n+6 s(0z – z)

Q: 16s? +37s - 30 Determine L (s+2)2(s – 3)

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Q: 8. 2.2 dr

A: As per our guidelines we are suppose to solve only first question if the multiple questions are…

Q: 3cos3x %3D s² + (v9)

A: We have to solve given problem:

Q: 8n+5 II (1+i) = k=1

A: To find ∏k=18n+51+i:

Q: Find A x B x C where A = {2, 5}., B = {13, 17}, C = {0} . O (2,13,0), (2, 17,0), (5, 13, 0), (5, 17,…

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Q: S Vi+ V2+3xdx

A: Since you have asked multiple question, we will solve the first question for you. If you want any…

Q: d2/dt2 (21t)

A: In general the second derivative is used to find the acceleration of an object . The second…

Q: 3xy If z determine 2x - 3y

A:

Q: 2. S 2z+8 dz (z+7)a

A: A detailed solution is given below

Q: dz 22 z²+4z S

A:

Q: 3a + 46° – 5 = 3 (6) +4(2) – 5 ? ||

A: Solution: The objective is to calculate the value

Q: x + y + z = 1 2 + 2 + 2 = 2 3 + 13 + 23 = 3 = 7 5 + + 5 + 2 9 = ? =

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Q: L4 for x2+1 고 on [-2,2]

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Q: * Let z1 = 2 + i and z2 = 5 + 2 i. Find 3 z1/ ( z1 - z2) - (12/ 10 ) - (3/10)i O (1/10 ) + ( 3/10) i…

A:

Q: I (n Ps)= 48 3 (nC4)

A: Solution

Q: 7(z+2)=2(z+3)

A: 7(z+2)=2(z+3)7×z+7×2=2×z+2×3

Q: 15. 423-922 + 72 +3)e- dz

A:

Q: Evaluate 3r+(6s)/(7), when r=3 and s=2 (21)/(7)

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Q: 4x+ 11 dx 423 11 4x 2x2 11 4x + 2x6 4x +c 2x2 11 4x+ +c 2x2 11 +c 6x2 4x + 4.

A:

Q: Find L S s²-48-7 Find L¹ 2s+6 s² +6s+34

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Q: L{2et – 4e4 } O 2(s-6) 52-6s+8 O2 (6-s) 52-6s+8 s-6 82 6s+8 (s 6) 2 6s+8

A:

Q: 3. (D5 –Dª – 2D³ +18D² –31D+15)y =0

A: Given differential equation is D5-D4-2D3+18D2-31D+15y = 0

Q: 3y +5 (5y-7)2 dy

A: We can find the integration as below.

Q: 6x2y³ - 12xy³ + 9x2y2z 3xy(xy 2xy + 3xy) O3a2y(2y2 - 2y1 +3yz) 4y³ + 3xz) О3xУ2 (2ху O O6xy³ (2xy³ —…

A: .

Q: 3(z+9)=

A: 3(z+9)=3z+9×3 By simplify the equation by open the bracket

Q: Find L - (8+3)3] 7 12 O 9t%e-3t O 6te3t O 6t?e-3t O 6t2

A: Use property of inverse laplace transform

Q: 4s+4 s2(s-2)

A:

Q: Evaluate L{(t²+ 4)e³t} 2(2s² – 12s + 19) а) 2(2s² - b) 12s + 19) (s + 3)2 (s – 3)2 (2s2 – 12s + 19)…

A:

Q: 4 (-1)*- k² k=2 3k II

A: Simplify the product as follows. ∏k=24-1k×k23k3=-12×22323-13×32333-14×42343

Q: -dz :+ 5: + 6 2

A:

Q: 3(z+5)=12

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Q: S(in 6x) dx x (In 6x)2 - 2x (In 6x) +c x (In 6x)2 - x (In 6x) + x + C <(In 6x)2 - 2x х (in 6x)2 + 2x…

A: