2HBr(g) = H₂(g) + Br₂(g) K = 2.86 x 10-5 @ 1490 K Calculate the equilibrium pressures of the components when the system is charged with 2.0 atm of HBr. What is the equilibrium pressure of Br2? ?] PBr₂ = [?] x 10¹¹ atm
2HBr(g) = H₂(g) + Br₂(g) K = 2.86 x 10-5 @ 1490 K Calculate the equilibrium pressures of the components when the system is charged with 2.0 atm of HBr. What is the equilibrium pressure of Br2? ?] PBr₂ = [?] x 10¹¹ atm
Introduction to General, Organic and Biochemistry
11th Edition
ISBN:9781285869759
Author:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
Publisher:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
Chapter7: Reaction Rates And Chemical Equilibrium
Section: Chapter Questions
Problem 7.28P: 7-28 When the following reaction reached equilibrium at 325 K, the equilibrium constant was found to...
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![2HBr(g) = H₂(g) + Br₂(g)
K = 2.86 x 10-5 @ 1490 K
Calculate the equilibrium pressures of
the components when the system is
charged with 2.0 atm of HBr. What is the
equilibrium pressure of Br2?
PBr₂ = [?] x 10 atm
Coefficient (green)
Exponent (yellow)
Enter](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F10288d49-a433-4131-955f-49105026c040%2F7aca7bcb-e491-4ae3-bcf8-c1d8c8125c7b%2Ffv5nyz9_processed.jpeg&w=3840&q=75)
Transcribed Image Text:2HBr(g) = H₂(g) + Br₂(g)
K = 2.86 x 10-5 @ 1490 K
Calculate the equilibrium pressures of
the components when the system is
charged with 2.0 atm of HBr. What is the
equilibrium pressure of Br2?
PBr₂ = [?] x 10 atm
Coefficient (green)
Exponent (yellow)
Enter
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