2х1 — 2х2 + 3х3 + 4x4 3D 33 5x2 7x3 + 3x4 4x3 – 5x4 = 3 5х1 + 4x2 + 6хз — 2х4 3 45 Зх1 — 5х2 — 7хз + 3х4 —D 11 4x1 + 3x2

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
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Evaluate using Gauss-Seidel Iteration 

2x1 – 2x2 + 3x3 + 4x4 = 33
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Зx, — 5х2 — 7хз + 3x, 3D 11
4x1 + 3x2 — 4хз — 5х4 3D 3
5x1 + 4x2 + 6хз — 2х4 3 45
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Transcribed Image Text:2x1 – 2x2 + 3x3 + 4x4 = 33 - Зx, — 5х2 — 7хз + 3x, 3D 11 4x1 + 3x2 — 4хз — 5х4 3D 3 5x1 + 4x2 + 6хз — 2х4 3 45 - -
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