2х at (1,1) (x+1) Find the equation of the line tangent to y = a) x-2y =-1 b) 2x-у - 1 c) х-у -2 d) 2x + y = 1

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A: (x-1)/2 = (y-1)/2 = (z-3)/2  And (x+1)/4 =y/3 =(z-1).

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