2C Jr-ct Question 1. Consider the second order partial differential equation (1) for an unknown real-valued function u = u(t, x), wheret represents time, x represents a point in space, and c > 0 is a constant. 1. For any twice differentiable functions F = F(x) and G = G(x), show that u(t, r) = F(x+ ct) + G(x – ct) satisfies (1). 1) are often solved as initial value problems, where the initial description of Partial differential equations such as the unknown function and its time derivative are provided at each point in space. Along these lines, suppose we are given that u(0, x) = 9(x) and (0, x) = h(x), for some given functions g and h. 2. Assume that u(t, x) = F(x + ct) + G(x - ct) for some functions F and G, as described in problem 1.1. If u = u(t, x) solves the initial value problem described above, show that g(x) = F(x)+ G(x) and h(x) = cF' (x) – cG"(x). 3. By integrating the last equation for h(x), show that for any constant a E R, | h(s) ds = cF(x) – cG(x) – cF(a) + cG(a), and from here solve a linear system to show that + (x)6 F(#) =; (9(x) + / h(s) ds + F(a) – G(a and 1 G(2) = (g(2) –| h(s) ds – F(a) + G(a) ). 4. Lastly, given that u(t, r) value problem for (1): = F(x + ct) + G(x – ct), arrive at an explicit formula for the solution to the initial 1 1 cr+ct u(t, a) = [9(x + ct)+ g(x – ct)] + h(s)ds.
2C Jr-ct Question 1. Consider the second order partial differential equation (1) for an unknown real-valued function u = u(t, x), wheret represents time, x represents a point in space, and c > 0 is a constant. 1. For any twice differentiable functions F = F(x) and G = G(x), show that u(t, r) = F(x+ ct) + G(x – ct) satisfies (1). 1) are often solved as initial value problems, where the initial description of Partial differential equations such as the unknown function and its time derivative are provided at each point in space. Along these lines, suppose we are given that u(0, x) = 9(x) and (0, x) = h(x), for some given functions g and h. 2. Assume that u(t, x) = F(x + ct) + G(x - ct) for some functions F and G, as described in problem 1.1. If u = u(t, x) solves the initial value problem described above, show that g(x) = F(x)+ G(x) and h(x) = cF' (x) – cG"(x). 3. By integrating the last equation for h(x), show that for any constant a E R, | h(s) ds = cF(x) – cG(x) – cF(a) + cG(a), and from here solve a linear system to show that + (x)6 F(#) =; (9(x) + / h(s) ds + F(a) – G(a and 1 G(2) = (g(2) –| h(s) ds – F(a) + G(a) ). 4. Lastly, given that u(t, r) value problem for (1): = F(x + ct) + G(x – ct), arrive at an explicit formula for the solution to the initial 1 1 cr+ct u(t, a) = [9(x + ct)+ g(x – ct)] + h(s)ds.
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Plz solve the q1 (and all its 4 parts with complete steps) . I need the answer in 2 hour also i attach the solution that u given to me. I don't need this plz give me a exact and perfect soloution with detail steps. A.and tamr a thumb up
![Question 1. Consider the second order partial differential equation
(1)
for an unknown real-valued function u = u(t, x), where t represents time, r represents a point in space, and c> 0 is
a constant.
1. For any twice differentiable functions F =
satisfies 1).
F(x) and G = G(x), show that u(t, x) = F(x + ct) + G(x – ct)
Partial differential equations such as 1)
the unknown function and its time derivative are provided at each point in space. Along these lines, suppose we are
given that u(0, x) = g(x) and (0, x) = h(x), for some given functions g and h.
are often solved as initial value problems, where the initial description of
2. Assume that u(t, x) = F(x + ct) + G(x – ct) for some functions F and G, as described in problem 1.1. If
u = u(t, x) solves the initial value problem described above, show that
g(x) = F(x) + G(x)
and
h(x) =
cF' (x) – eG' (x).
3. By integrating the last equation for h(x), show that for any constant a E R,
| h(s) ds = cF(x) – cG(x) – cF(a)+cG(a),
and from here solve a linear system to show that
F(2) = (a(e) + hle) des + F(a) – G(a)).
and
G(=) =; (9(=) – h(») ds – F(a) + G(a)) .
4. Lastly, given that u(t, x) = F(x + ct) + G(x – ct), arrive at an explicit formula for the solution to the initial
value problem for 1):
1
1
cr+ct
u(t, z) = ; [g(x + ct) + g(x – ct)] +
h(e)ds.
2c
r-ct](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F5b6ea445-fcb8-43e5-8ecc-e13cb9c0bb44%2F8f80c2fb-30e8-491d-92ab-9b42b2092466%2F1gqfu8c_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Question 1. Consider the second order partial differential equation
(1)
for an unknown real-valued function u = u(t, x), where t represents time, r represents a point in space, and c> 0 is
a constant.
1. For any twice differentiable functions F =
satisfies 1).
F(x) and G = G(x), show that u(t, x) = F(x + ct) + G(x – ct)
Partial differential equations such as 1)
the unknown function and its time derivative are provided at each point in space. Along these lines, suppose we are
given that u(0, x) = g(x) and (0, x) = h(x), for some given functions g and h.
are often solved as initial value problems, where the initial description of
2. Assume that u(t, x) = F(x + ct) + G(x – ct) for some functions F and G, as described in problem 1.1. If
u = u(t, x) solves the initial value problem described above, show that
g(x) = F(x) + G(x)
and
h(x) =
cF' (x) – eG' (x).
3. By integrating the last equation for h(x), show that for any constant a E R,
| h(s) ds = cF(x) – cG(x) – cF(a)+cG(a),
and from here solve a linear system to show that
F(2) = (a(e) + hle) des + F(a) – G(a)).
and
G(=) =; (9(=) – h(») ds – F(a) + G(a)) .
4. Lastly, given that u(t, x) = F(x + ct) + G(x – ct), arrive at an explicit formula for the solution to the initial
value problem for 1):
1
1
cr+ct
u(t, z) = ; [g(x + ct) + g(x – ct)] +
h(e)ds.
2c
r-ct
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