2a? + 2y? + 8x + 4y + 8 = 0 is the equation of a circle with center (h, k) and radius r for: h and k and ||

Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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The given equation is:

\[ 2x^2 + 2y^2 + 8x + 4y + 8 = 0 \]

This is the equation of a circle with center \((h, k)\) and radius \(r\).

**Find the values:**

- \( h = \) [input box]
- \( k = \) [input box]
- \( r = \) [input box]

To solve for \(h\), \(k\), and \(r\), you need to rewrite the equation in the standard form of a circle. This involves completing the square for both \(x\) and \(y\) terms.
Transcribed Image Text:The given equation is: \[ 2x^2 + 2y^2 + 8x + 4y + 8 = 0 \] This is the equation of a circle with center \((h, k)\) and radius \(r\). **Find the values:** - \( h = \) [input box] - \( k = \) [input box] - \( r = \) [input box] To solve for \(h\), \(k\), and \(r\), you need to rewrite the equation in the standard form of a circle. This involves completing the square for both \(x\) and \(y\) terms.
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