290+342 = %3D - * 29= 243 -6 – 342 %3D * -3 -4- %3D | Differentiate batheides with resefect to h', we get dg dh | dg dh *- (34) - o - {(24) h? -3h dh Again diferentiate bothrides with sasfect to h' we get dig dh? 器=去(4-3) 3去(4) dh 2h -3(1) -3 +2h %3D

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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I just need the step by step explanation  about this solution that I can share in my class. It should probably a sentence form. Thank youuu

242 - 6
a 29= 243-6 – 34?
2go+342 =
%3D
Differentiate betheides with sesfect to h',
we get
dg
-
dh
dg
dh
*- ( 344) - o
-콘(21)
*= 42 - 3h
dh
Again differentiate bothrides with zafect to 'h'
get
we
dig
- (4*- 34)
%3D
%3D
-
dh
2h -3(1)
- -3+2h
Transcribed Image Text:242 - 6 a 29= 243-6 – 34? 2go+342 = %3D Differentiate betheides with sesfect to h', we get dg - dh dg dh *- ( 344) - o -콘(21) *= 42 - 3h dh Again differentiate bothrides with zafect to 'h' get we dig - (4*- 34) %3D %3D - dh 2h -3(1) - -3+2h
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