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29, 8. Find the charge on the capaitor of an RLC series circuit at time t, if L = 1 henry, R C = 0.25 farad, and E(t) = 50 cos(t) volts, given the initial conditions q(0) = 150/13 C and q'(0)=200/13 C. Solution: q(t) 100/3 39 e sin (√3t) + 100 13 sin(t) + 150 13 -cos(t)

29, 8. Find the charge on the capaitor of an RLC series circuit at time t, if L = 1 henry, R C = 0.25 farad, and E(t) = 50 cos(t) volts, given the initial conditions q(0) = 150/13 C and q'(0)=200/13 C. Solution: q(t) 100/3 39 e sin (√3t) + 100 13 sin(t) + 150 13 -cos(t)

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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Find the charge on the capaitor of an RLC series circuit at time t, if L = 1 henry, R = 29, C = 0.25 farad, and E(t) = 50 cos(t) volts, given the initial conditions q(0) 150/13 C and q'(0) = 200/13 C. Solution: Solution: q(t)= 9. Find the Laplace transform of the function is 100√3 39 10. The inverse Laplace transform of Solution: 150 -esin(√3t) + sin(t) + cos(t) 100 13 13 f(t) = (et-e-t)³ L{f(t)} F(s) 84 1082 +9 6s +3 s4 + 58² +4 L-¹{F(s)} = sin(t) + 2 cos(t) + 85(5²7) - sin(2t) - 4 cos(2t) 2
Transcribed Image Text:Find the charge on the capaitor of an RLC series circuit at time t, if L = 1 henry, R = 29, C = 0.25 farad, and E(t) = 50 cos(t) volts, given the initial conditions q(0) 150/13 C and q'(0) = 200/13 C. Solution: Solution: q(t)= 9. Find the Laplace transform of the function is 100√3 39 10. The inverse Laplace transform of Solution: 150 -esin(√3t) + sin(t) + cos(t) 100 13 13 f(t) = (et-e-t)³ L{f(t)} F(s) 84 1082 +9 6s +3 s4 + 58² +4 L-¹{F(s)} = sin(t) + 2 cos(t) + 85(5²7) - sin(2t) - 4 cos(2t) 2
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