29-30. The shaded region in the given figure above illustrates an unboundedfeasible region. Which of the following is true? 1. The maximum value for theobjective function does not exist in an unbounded feasible region. II. If theobjective function is Min Z=x+y, then it's maximum is 25 at (25,0). III. If theobjective function is Max Z=-x+2y, then it's minimum is O at (25,0). IV. Unboundedfeasible regions have either maximum or minimum value.(0.24)50-20-10A. IB. IIC. I and IID. III and IV10.-10(12)10(15,5)(25.0)40

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Answered: 29-30. The shaded region in the given…

Advanced Engineering Mathematics

10th Edition

ISBN:9780470458365

Author:Erwin Kreyszig

Publisher:Erwin Kreyszig

Chapter2: Second-order Linear Odes

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Part 1 In this problem you will maximize and minimize the objective function P = 2x + 4y subject to the following constraints: 10х + 7у 2 10 —2х + 8y < 280 12х — 1у < 670 | How many corner points does the system have? • Part 2 Write all corner points in the space provided ere are multiple corner points, write each ordered pair seperated by a below. If comma.
11 Consider the problem. Min s.t. 2x² 18x + 2XY+Y2 - 16Y + 54 X + 4Y ≤ 8 (a) Find the values of X and Y that minimize the function and find the optimal solution value. at (X, Y) = (b) If the right-hand side of the constraint is increased from 8 to 9, how much do you expect the objective function to change? Based on the dual value on the constraint X + 4Y ≤ 8, we expect the optimal objective function value to decrease by (c) Resolve the problem with a new right-hand side of the constraint of 9. How does the actual change compare with your estimate? , so the actual change is a decrease of If we resolve the problem with a new right-hand-side of 9 the new optimal objective function value is rather than what we expected in part (b).
29-30. The shaded region in the given figure above illustrates an unbounded feasible region. Which of the following is true? 1. The maximum value for the objective function does not exist in an unbounded feasible region. II. If the objective function is Min Z=x+y, then it's maximum is 25 at (25,0). III. If the objective function is Max Z=-x+2y, then it's minimum is O at (25,0). IV. Unbounded feasible regions have either maximum or minimum value. (0,24) 50 -10 -20 O A. I B. II C. I and II D. III and IV 20 10 0 -10 (12) 10 (15.5) (25.0) 40
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The graph to the right shows a region of feasible solutions. Use this region to find maximum and minimum values of the given objective functions, and the locations of these values on the graph. a. z = 3x + 5y b. z = 2x + 3y c. z = 5x + 2y d. z = x + 5y a. Select the correct choice below and, if necessary, fill in the answer box to complete your choice. A. The maximum value of z = 3x + 5y is at (Type integers or decimals.) OB. The maximum does not exist. Select the correct choice below and, if necessary, fill in the answer box to complete your choice. OA. The minimum value of z = 3x + 5y is (Type integers or decimals.) t exist. at OB. The minimum does b. Select the correct choice below and, if necessary, fill in the answer box to complete your choice. OA. The maximum value of the objective function z = 2x + 3y is (Type integers or decimals.) OB. The maximum does not exist. at 4
Solve the LP problem. If no optimal solution exists, indicate whether the feasible region is empty or the objective function is unbounded. (Enter EMPTY if the region is empty. Enter UNBOUNDED if the function is unbounded.) Maximize p = 4x + 3y subject to -4x + y 2 7 x + 5y ≤ 9 x ≥ 0, y ≥ 0. p = (x, y) =
Solve the LP problem. If no optimal solution exists, indicate whether the feasible region is empty or the objective function is unbounded. (Enter EMPTY if the region is empty. Enter UNBOUNDED if the function is unbounded.) Maximize p = 3x + y subject to 2x – 3y<0 Зх — 2y 20 x + y55 x 2 0, y 2 0. p = (х, у) %3
Multiple choice: You were given the following mathematical statements: Maximize: 200x +150y; Subject to: x >= 2; 2y <= 6; 3x + 4y <= 10; and non-negativity condition, x >= 0 and y >= 0. Should the solution value for the first, second and third constraint amount to one (1), seven (7), and eleven (11), respectively, does it mean a valid optimal solution can be found? • No• Answer is not given• Cannot be determined• Yes
The shaded region in the given figure above illustrates an unbounded feasibleregion. Which of the following is true?I. The maximum value for the objective function does not exist in an unboundedfeasible region.II. If the objective function is Min Z=x+y, then it’s maximum is 25 at (25,0).III. If the objective function is Max Z=-x+2y, then it’s minimum is 0 at (25,0).IV. Unbounded feasible regions have either maximum or minimum value.A. IB. IIC. I and IID. III and IV
You are given a feasible region. Find the maximum and minimum (if they exist) for the given objective function. (If an answer does not exist, enter DNE.) z = 10x + 28y maximum minimum y 0 (0,33) (2,25) (5,15) (11,0)

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