28. Let X have a Standard Normal Distribution. Find P(X > - 0.25).A. 0.49871B. 0.59871C. 0.69871D. 0.79871

Given that: Z is standard normal Distributed with i.e. mean µ =0 and standard deviation σ =1 By…

Answered: 28. Let X have a Standard Normal…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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9. Which of the following statements is not a characteristic of the standard normal distribution below? Normal Distribution Curve Density 0.4 -1 0.3 0.2 0.1 -3 -2 A. The total area under the curve equals 1. B. The standard normal distribution curve has a fixed mean of 0. C. The standard normal distribution curve has a fixed standard deviation of 1. D. The normal distribution curve has left tail that extend infinitely. E. The standard normal distribution curve is negatively skewed. F. The normal distribution curve has right tail that extend infinitely. 2 3 curve shown
46. Let X have a Standard Normal Distribution. Find a such that P(X > a) = 0.80511 %3| A. – 0.66 В. — 0.76 С. — 0.86 D. – 0.96
2. In a standard normal curve, find... a) P(Zs 2.80) = p (2.80) b) between z=-1.28 and z=-0.663B c) to the left of z=1.50;
45. Let X have a Standard Normal Distribution. Find a such that P(X < a) = 0.88877 А. 0.92 В. 1.02 С. 1.12 D. 1.22
APEAS of a Standard Normal Distribution (b) Tuble of Areas to the Left of z When z Is Pusitive .00 .01 .02 .03 .04 .05 .06 .07 ,08 .09 (a) Table of Areas to the Lefi of z When z Is Negative 0,0 5000 .5040 5080 .5120 5160 5199 .5239 5279 .5319 .5359 .00 .01 03 -3.4 .0003 .0003 .0003 .0003 .0003 .0003 .0003 .0003 .0003 02 .04 05 06 .07 08 09 0.1 5398 .5438 5478 .5517 5557 5596 .5636 5675 .5714 .5753 .0002 0.2 .5793 .5832.5871 5910 .5948 5987 .6026 ,6064 6103 .6141 -3.3 .0005 .0005 .0005 .0004 .0004 .0004 .0004 .0004 .0004 s the areu to the .0003 0.3 .6179 ,6217 ,6255 .6293 .6331 .6368 .6406 6443 .6480 .6517 -3.2 .0007 .0007 .0006 .0006 .0006 .0006 .0006 .0005 .0005 .0005 0,4 .6554 .6591 .6628 .6664 .6700 .6736 .6772 .6808 .6844 .6879 -3.1 ,0010 ,0009 0009 .0009 .0008 .0008 .0008 ,0008 .0007 „6915 6950 6985 .7019 .7054 .7088 .7123 .7157 7190 .7224 0.5 .0007 -3.0 .0013 ,0013. .0013 .0012 .0012 0011 .0011 .0011 .0010 .0010 0.6 .7257 7291 .7324 .7357 .7389 .7422 .7454 '.7486 .7517 .7549 -2.9…
Let X follow the normal distribution with μ = 100 and σ = 10. Then P(X < 120) is closest to: a. 0.023 b. 0.046 c. 0.430 d. 0.853 e. 0.977
6.9 To enter the cumulative normal distribution table Þ(Z), calculate Z and Z at the spec limits. upper lower Þ(2) = 0.9772 and Þ(-2) = 0.0228, the area to the right of the USL plus to the left of the LSL is 0.0456.
A normal distribution has μ = 32 and σ = 5. Find the z score corresponding to x = 27. Find the z score corresponding to x = 46. Find the raw score corresponding to z = −3. Find the raw score corresponding to z = 1.1.
Jj.177.
4. Find the area of the standard normal distribution between z=-o.67 and z=0 5. Cheryl has taken two quizes in her history class. She scired 15 on the second quiz, fo which mean of all scores
Let the random variable Z follow a standard normal distribution. a. Find P(Z 1.73). c. Find P(Z - 1.32). e. Find P(1.07
33. Let X have a Nonstandard Normal Distribution with u = 55 and o = 8. Find P(X < 59). C. 0.70146 A. 0.68146 B. 0.69146 D. 0.71146

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28. Let X have a Standard Normal Distribution. Find P(X > -0.25). B. 0.59871 A. 0.49871 C. 0.69871 D. 0.79871