28. Let E be the electric field due to a long, uniformly charged rod of ra- dius R with charge density 8 per unit length (Figure 21). By symmetry, we may assume that E is everywhere perpendicular to the rod and its mag- nitude E(d) depends only on the distance d to the rod (strictly speaking, this would hold only if the rod were infinite, but it is nearly true if the rod is long enough). Show that E(d) = 8/2re0d for d > R. Hint: Apply Gauss's Law to a cylinder of radius R and of unit length with its axis along the rod. E -R Charged rod FIGURE 21
28. Let E be the electric field due to a long, uniformly charged rod of ra- dius R with charge density 8 per unit length (Figure 21). By symmetry, we may assume that E is everywhere perpendicular to the rod and its mag- nitude E(d) depends only on the distance d to the rod (strictly speaking, this would hold only if the rod were infinite, but it is nearly true if the rod is long enough). Show that E(d) = 8/2re0d for d > R. Hint: Apply Gauss's Law to a cylinder of radius R and of unit length with its axis along the rod. E -R Charged rod FIGURE 21
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![28. Let E be the electric field due to a long, uniformly charged rod of ra-
dius R with charge density 8 per unit length (Figure 21). By symmetry,
we may assume that E is everywhere perpendicular to the rod and its mag-
nitude E(d) depends only on the distance d to the rod (strictly speaking,
this would hold only if the rod were infinite, but it is nearly true if the
rod is long enough). Show that E(d) = 8/2re0d for d > R. Hint: Apply
Gauss's Law to a cylinder of radius R and of unit length with its axis along
the rod.
E
-R
Charged rod
FIGURE 21](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F56b2b2de-6b92-415e-a79a-7d7c6dff980e%2F98934bdb-d9a3-4a99-80e3-a51245404291%2Fgegxpb.png&w=3840&q=75)
Transcribed Image Text:28. Let E be the electric field due to a long, uniformly charged rod of ra-
dius R with charge density 8 per unit length (Figure 21). By symmetry,
we may assume that E is everywhere perpendicular to the rod and its mag-
nitude E(d) depends only on the distance d to the rod (strictly speaking,
this would hold only if the rod were infinite, but it is nearly true if the
rod is long enough). Show that E(d) = 8/2re0d for d > R. Hint: Apply
Gauss's Law to a cylinder of radius R and of unit length with its axis along
the rod.
E
-R
Charged rod
FIGURE 21
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