28 ### Problem 28**Text:**(II) Point \( a \) is 26 cm north of a \(-3.8 \mu C \) point charge, and point \( b \) is 36 cm west of the charge (Fig. 23–27). Determine(a) \( V_b - V_a \), and(b) \( \vec{E}_b - \vec{E}_a \) (magnitude and direction).**Figure 23-27:**- The diagram shows a point charge \( Q = -3.8 \mu C \).- Point \( a \) is located 26 cm directly to the north (upward) from the charge.- Point \( b \) is located 36 cm directly to the west (left) from the charge.- The figure visually represents the positions of points \( a \) and \( b \) with respect to the charge \( Q \).**Detailed Description of the Diagram:** - The charge \( Q \) is situated at the origin of the coordinate system.- The \( y \)-axis shows a mark at 26 cm directly above the charge for point \( a \).- The \( x \)-axis shows a mark at 36 cm directly to the left of the charge for point \( b \).- Both points \( a \) and \( b \) are marked along with dotted horizontal and vertical lines from the origin to indicate their respective distances from the charge.---This problem involves calculating the electric potential difference \( V_b - V_a \) and the electric field difference \( \vec{E}_b - \vec{E}_a \) given specific positions relative to a point charge.

Answered: Image /qna-images/answer/a7f2490d-f310-4251-b50b-0d5718e0a8c5.jpg

28. (II) Point a is 26 cm north of a -3.8 μC point charge, and point b is 36 cm west of the charge (Fig. 23-27). Determine (a) V – V₂, and (b) E₁ - E₂ (magnitude and direction). FIGURE 23-27 b Problem 28. 26 cm 36 cm Q=-3.8 μс

28. (II) Point a is 26 cm north of a -3.8 μC point charge, and point b is 36 cm west of the charge (Fig. 23-27). Determine (a) V – V₂, and (b) E₁ - E₂ (magnitude and direction). FIGURE 23-27 b Problem 28. 26 cm 36 cm Q=-3.8 μс

College Physics

10th Edition

ISBN:9781285737027

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter15: Electric Forces And Electric Fields

Section: Chapter Questions

Problem 64AP: a point charge of magnitude 5.00 C is at the origin of a coordinate system, and a charge of 4.00 C...

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Question

### Problem 28

**Text:**
(II) Point \( a \) is 26 cm north of a \(-3.8 \mu C \) point charge, and point \( b \) is 36 cm west of the charge (Fig. 23–27). Determine
(a) \( V_b - V_a \), and
(b) \( \vec{E}_b - \vec{E}_a \) (magnitude and direction).

**Figure 23-27:**
- The diagram shows a point charge \( Q = -3.8 \mu C \).
- Point \( a \) is located 26 cm directly to the north (upward) from the charge.
- Point \( b \) is located 36 cm directly to the west (left) from the charge.
- The figure visually represents the positions of points \( a \) and \( b \) with respect to the charge \( Q \).

**Detailed Description of the Diagram:**
- The charge \( Q \) is situated at the origin of the coordinate system.
- The \( y \)-axis shows a mark at 26 cm directly above the charge for point \( a \).
- The \( x \)-axis shows a mark at 36 cm directly to the left of the charge for point \( b \).
- Both points \( a \) and \( b \) are marked along with dotted horizontal and vertical lines from the origin to indicate their respective distances from the charge.

---

This problem involves calculating the electric potential difference \( V_b - V_a \) and the electric field difference \( \vec{E}_b - \vec{E}_a \) given specific positions relative to a point charge.

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