28. A simple curve have tangents AB and BC intersecting at a common point B. AB has an azimuth of 180° and BC has an azimuth og 230°. The stationing of the point of curvature at A is 10 + 140.26. If the degree of the simple curve is 4". Compute the stationing of point "X" on the curve on which a line passing through the center of the curve makes an angle of 58° with the line AB, intersects the curve at "X". ANS: 10 + 300.26

28. A simple curve have tangents AB and BC intersecting at a common point B. AB has an azimuth of 180° and BC has an azimuth og 230°. The stationing of the point of curvature at A is 10 + 140.26. If the degree of the simple curve is 4". Compute the stationing of point "X" on the curve on which a line passing through the center of the curve makes an angle of 58° with the line AB, intersects the curve at "X". ANS: 10 + 300.26

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Question

28. A simple curve have tangents AB and BC intersecting at a common point B. AB has an azimuth of
180° and BC has an azimuth og 230°. The stationing of the point of curvature at A is 10 +140.26.
If the degree of the simple curve is 4°. Compute the stationing of point "X" on the curve on
which a line passing through the center of the curve makes an angle of 58° with the line AB,
intersects the curve at "X".
ANS: 10 + 300.26
29 A simnle curve connects two tangents AR and BC with hearing N 85°30' E and S 68°30'E

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