28. 25.00 mL of a solution of a weak monoprotic acid, HX, was titrated with a 0.0640 M solution of NaOH, requiring 18.22 mL to neutralize the acid. If the Ka for the acid is 3.60*10-6, calculate the number of moles of a salt, NaX, that must be added to produce a pH of 6.00 in 150.00 mL of the original solution. You may assume that the temperature is 25 °C. It is impossible for a solution with this composition to have a pH of 6.00 0.00117 mol 0.0252 mol 0.0466 mol O 1.17 mol
28. 25.00 mL of a solution of a weak monoprotic acid, HX, was titrated with a 0.0640 M solution of NaOH, requiring 18.22 mL to neutralize the acid. If the Ka for the acid is 3.60*10-6, calculate the number of moles of a salt, NaX, that must be added to produce a pH of 6.00 in 150.00 mL of the original solution. You may assume that the temperature is 25 °C. It is impossible for a solution with this composition to have a pH of 6.00 0.00117 mol 0.0252 mol 0.0466 mol O 1.17 mol
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![28.
25.00 mL of a solution of a weak monoprotic acid, HX, was titrated
with a 0.0640M solution of NaOH, requiring 18.22 mL to neutralize
the acid. If the Ka for the acid is 3.60*106, calculate the number of
moles of a salt, NaX, that must be added to produce a pH of 6.00 in
150.00 mL of the original solution. You may assume that the
temperature is 25 °C.
It is impossible for a solution with this composition to have a pH of
6.00
0.00117 mol
0.0252 mol
0.0466 mol
1.17 mol](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc30c2338-d561-4cbd-9b51-3432f4a2cf2c%2F80814f8e-d20c-4209-b10d-ef6090b76292%2Fnlnazh_processed.png&w=3840&q=75)
Transcribed Image Text:28.
25.00 mL of a solution of a weak monoprotic acid, HX, was titrated
with a 0.0640M solution of NaOH, requiring 18.22 mL to neutralize
the acid. If the Ka for the acid is 3.60*106, calculate the number of
moles of a salt, NaX, that must be added to produce a pH of 6.00 in
150.00 mL of the original solution. You may assume that the
temperature is 25 °C.
It is impossible for a solution with this composition to have a pH of
6.00
0.00117 mol
0.0252 mol
0.0466 mol
1.17 mol
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