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= 27000HZ = 4.1cos(0*)V >4.1<0*V C2 R1 7.3E-06 2.7E+03 V1 32pi(f) =>2pi(27000) =>54000pi AC 4.1 0 L1 9.9E-03 3.2E R2 .ac lin 10 1 30000 860

= 27000HZ = 4.1cos(0*)V >4.1<0*V C2 R1 7.3E-06 2.7E+03 V1 32pi(f) =>2pi(27000) =>54000pi AC 4.1 0 L1 9.9E-03 3.2E R2 .ac lin 10 1 30000 860

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Calculate the current through and voltage over C1,C2,R1,R2,L1

f = 27000HZ V = 4.1cos(0*)V C2 R1 =>4.1<0*V 7.3E-06 2.7E+03 V1 w=2pi(f) =>2pi(27000) =>54000pi AC 4.1 0 C1 L1 9.9E-03 3.2E-06 R2 .ac lin 10 1 30000 860
Transcribed Image Text:f = 27000HZ V = 4.1cos(0*)V C2 R1 =>4.1<0*V 7.3E-06 2.7E+03 V1 w=2pi(f) =>2pi(27000) =>54000pi AC 4.1 0 C1 L1 9.9E-03 3.2E-06 R2 .ac lin 10 1 30000 860
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