27. х %3D ソ= z = 43 L 23 2х + 5 4х - 3 y A R

Q: Differer

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A: Here,

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A: Given: I=∫12lnxx2dx   Apply the integration by parts to solve the given integral. ∫udv=u·v-∫vdu

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A: This is the Linear first order diffrential equation. I have added a photo below, in which i written…

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A: We have to solve the given equation. The given equation is 2-dydX=y2X2+yX+1    ......(1)

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A: Solve this equation by logical interpretation like simplifying the denominator and then follow.

Q: (4х* — 4х у + Зу* + 2) dx +x(2х — 2у + 1) dу %3D0

A: missing details.

Q: T= tan (x+2y+ 3Z) %3D Find: Txx XX Tx Txy Ty Tyy Tyx Tz Tzz Tzx T zy

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Q: Find oy for dx2

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