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27. Bob selects independent random samples from two populations and obtains the values p1 0.700 and p2 = 0.500. He constructs the 95% confidence interval for p1 P2 and gets: - 0.200 + 1.96(0.048) = 0.200±0.094. Note that 0.048 is called the estimated standard error of p1 – p2 (the ESE of the estimate). Tom wants to estimate the mean of the success rates: Pi + P2 2 (a) Calculate Tom's point estimate. (b) Given that the estimated standard er- ror of (pi + p2)/2 is 0.024, calculate the 95% confidence interval estimate of (n1 + no)/2 Hint: The answer has o our

27. Bob selects independent random samples from two populations and obtains the values p1 0.700 and p2 = 0.500. He constructs the 95% confidence interval for p1 P2 and gets: - 0.200 + 1.96(0.048) = 0.200±0.094. Note that 0.048 is called the estimated standard error of p1 – p2 (the ESE of the estimate). Tom wants to estimate the mean of the success rates: Pi + P2 2 (a) Calculate Tom's point estimate. (b) Given that the estimated standard er- ror of (pi + p2)/2 is 0.024, calculate the 95% confidence interval estimate of (n1 + no)/2 Hint: The answer has o our

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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27. Bob selects independent random samples from two populations and obtains the values p1 0.700 and p2 = 0.500. He constructs the 95% confidence interval for p1 P2 and gets: | 0.200 + 1.96(0.048) = 0.200±0.094. Note that 0.048 is called the estimated standard error of pi – P2 (the ESE of the estimate). Tom wants to estimate the mean of the success rates: Pi + P2 2 (a) Calculate Tom's point estimate. (b) Given that the estimated standard er- ror of (p1 + P2)/2 is 0.024, calculate the 95% confidence interval estimate of (p1 + P2)/2. Hint: The answer has our usual form: Pt. est. + 1.96 × ESE of the estimate.
Transcribed Image Text:27. Bob selects independent random samples from two populations and obtains the values p1 0.700 and p2 = 0.500. He constructs the 95% confidence interval for p1 P2 and gets: | 0.200 + 1.96(0.048) = 0.200±0.094. Note that 0.048 is called the estimated standard error of pi – P2 (the ESE of the estimate). Tom wants to estimate the mean of the success rates: Pi + P2 2 (a) Calculate Tom's point estimate. (b) Given that the estimated standard er- ror of (p1 + P2)/2 is 0.024, calculate the 95% confidence interval estimate of (p1 + P2)/2. Hint: The answer has our usual form: Pt. est. + 1.96 × ESE of the estimate.
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