27. Bob selects independent random samples fromtwo populations and obtains the values p10.700 and p2 = 0.500. He constructs the 95%confidence interval for p1P2 and gets:|0.200 + 1.96(0.048) = 0.200±0.094.Note that 0.048 is called the estimated standarderror of pi – P2 (the ESE of the estimate).Tom wants to estimate the mean of the successrates:Pi + P22(a) Calculate Tom's point estimate.(b) Given that the estimated standard er-ror of (p1 + P2)/2 is 0.024, calculatethe 95% confidence interval estimate of(p1 + P2)/2. Hint: The answer has ourusual form:Pt. est. + 1.96 × ESE of the estimate.

Answered: Image /qna-images/answer/9247c2bf-1cde-48c0-91a5-16f329da0876.jpg

Answered: 27. Bob selects independent random…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Eric is interested in how sleep deprivation effects performance on a learning task. Eric takes a sample of 10k (10, 000) rats subjects them to a learning task, he then keeps them up for a full 24 hours to ensure that they are sleep deprived. At this point he has them do the learning task again. He now wants to calculate the 95% confidence interval around the mean difference, which of the following formulas should he use: a. mD±1.96(smD) b. m±1.96(σm) c. m1-m2±1.96(sm1-m2) d. m1-m2±1.645(sm1-m2) e. mD±1.645(smD)
A simple random sample of size n = 40 is drawn from a population. The sample mean is found to be x = 121.2 and the sample standard deviation is found to be s = 12.6. Construct a 99% confidence interval for the population mean. The lower bound is (Round to two decimal places as needed.) The upper bound is . (Round to two decimal places as needed.)
A simple random sample of size n is drawn from a population that is normally distributed. The sample mean, x, is found to be 19.4, and the sample standard deviation, s, is found to be 4.3. (a) Construct a 95% confidence interval about μ if the sample size, n, is 31. (b) Construct a 95% confidence interval about μ if the sample size, n, is 63. How does increasing the sample size affect the margin of error, E? (c) Construct a 98% confidence interval about μ if the sample size, n, is 31.How does increasing the level of confidence affect the size of the margin of error, E? (d) If the sample size is 21, what conditions must be satisfied to compute the confidence interval?
A simple random sample of size n is drawn from a population that is normally distributed. The sample mean, x, is found to be 19.6, and the sample standard deviation, s, is found to be 5.6. (a) Construct a 98% confidence interval about u if the sample size, n, is 32. (b) Construct a 98% confidence interval about µ if the sample size, n, is 58. How does increasing the sample size affect the margin of error, E? (c) Construct a 99% confidence interval about u if the sample size, n, is 32. How does increasing the level of confidence affect the size of the margin of error, E? (d) If the sample size is 21, what conditions must be satisfied to compute the confidence interval? (a) Construct a 98% confidence interval about µ if the sample size, n, is 32. Lower bound:; Upper bound: (Round to two decimal places as needed.) C...
27. Bob selects independent random samples from two populations and obtains the values î1 0.700 and p2 = 0.500. He constructs the 95% confidence interval for p1 – P2 and gets: 0.200 + 1.96(0.048) = 0.200 ± 0.094. Note that 0.048 is called the estimated standard error of pi – p2 (the ESE of the estimate). Tom wants to estimate the mean of the success rates: Pi +P2 2 (a) Calculate Tom's point estimate. (b) Given that the estimated standard er- ror of (p1 + P2)/2 is 0.024, calculate the 95% confidence interval estimate of (Pi + P2)/2. Hint: The answer has our usual form: Pt. est. +1.96 × ESE of the estimate.
A simple random sample with n = 52 provided a sample mean of 24.0 and a sample standard deviation of 4.6. a. Develop a 90% confidence interval for the population mean (to 1 decimal). b. Develop a 95% confidence interval for the population mean (to 1 decimal). c. Develop a 99% confidence interval for the population mean (to 1 decimal). d. What happens to the margin of error and the confidence interval as the confidence level is increased? V - Select your answer - They increase They decrease They stay the same It cannot be determined from the given data The margin of error increases and the confidence interval becomes narrower The margin of error decreases and the confidence interval becomes wider
A simple random sample with n= 52 provided a sample mean of 23.0 and a sample standard deviation of 4.3. a. Develop a 90% confidence interval for the population mean (to 1 decimal). b. Develop a 95% confidence interval for the population mean (to 1 decimal). c. Develop a 99% confidence interval for the population mean (to 1 decimal). d. What happens to the margin of error and the confidence interval as the confidence level is increased? - Select your answer -
b )part?
12. Two independent samples are taken from two populations. Sample 1 has a mean of 12.8, a standard deviation of 2.3, and a sample size of 18. Sample 2 has a mean of 14.2, a standard deviation of 5.2, and a sample size of 23. This gives a standard error se(Ã1 — Ă2) = 1.212. A 95% confidence interval for the difference between the two means is: (A) (-2.00, -0.80). (B) (11.66, 13.94). (C) (-3.96, 1.16). (D) (-3.85, 1.05). (E) (-3.78, 0.98).
A sample of n = 7 scores is selected from a population with an unknown mean ( µ). The sample has a mean of M = 40 and a variance of s 2 = 63. Which of the following is the correct 95% confidence interval for µ?
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