27. Bob-draws a simple random sample from an extremely large population of lemons. The sample size n = 700 and in the sample 250 lemons turn out to be good and 450 lemons turn out to be bad. Find the confidence interval for the population proportion p of good lemons. A. (0.30165, 0.37264) C. (0.32165, 0.39264) B. (0.31165, 0.38264) D. (0.33165, 0.40264)

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**Problem 27: Confidence Interval for Lemon Quality**

Bob draws a simple random sample from an extremely large population of lemons. The sample size is \( n = 700 \), where 250 lemons are found to be good and 450 lemons are found to be bad. Determine the 95% confidence interval for the population proportion \( p \) of good lemons.

**Choices:**

A. (0.30165, 0.37264)  
B. (0.31165, 0.38264)  
C. (0.32165, 0.39264)  
D. (0.33165, 0.40264)  

**Solution Approach:**

To calculate the confidence interval, use the formula for the confidence interval for a population proportion:

\[
\hat{p} = \frac{\text{Number of good lemons}}{\text{Total sample size}} = \frac{250}{700} 
\]

Next, find the standard deviation for the sample proportion:

\[
\sigma_{\hat{p}} = \sqrt{\frac{\hat{p}(1-\hat{p})}{n}}
\]

Finally, use the z-score for a 95% confidence level (approximately 1.96) to find the margin of error and construct the confidence interval:

\[
CI = \hat{p} \pm z \times \sigma_{\hat{p}}
\]

Evaluate which of the given options corresponds to the calculated interval.
Transcribed Image Text:**Problem 27: Confidence Interval for Lemon Quality** Bob draws a simple random sample from an extremely large population of lemons. The sample size is \( n = 700 \), where 250 lemons are found to be good and 450 lemons are found to be bad. Determine the 95% confidence interval for the population proportion \( p \) of good lemons. **Choices:** A. (0.30165, 0.37264) B. (0.31165, 0.38264) C. (0.32165, 0.39264) D. (0.33165, 0.40264) **Solution Approach:** To calculate the confidence interval, use the formula for the confidence interval for a population proportion: \[ \hat{p} = \frac{\text{Number of good lemons}}{\text{Total sample size}} = \frac{250}{700} \] Next, find the standard deviation for the sample proportion: \[ \sigma_{\hat{p}} = \sqrt{\frac{\hat{p}(1-\hat{p})}{n}} \] Finally, use the z-score for a 95% confidence level (approximately 1.96) to find the margin of error and construct the confidence interval: \[ CI = \hat{p} \pm z \times \sigma_{\hat{p}} \] Evaluate which of the given options corresponds to the calculated interval.
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