27. Bob draws a simple random sample from an extremely large population of lemons. The sample sizen = 700 and in the sample 250 lemons turn out to be good and 450 lemons turn out to be bad. Find the Sconfidence interval for the population proportion p of good lemons.A. (0.30165, 0.37264)C. (0.32165, 0.39264)B. (0.31165, 0.38264)D. (0.33165, 0.40264)

Here we need to find confidence interval for population proportion p of good lemons.

Answered: 27. Bob-draws a simple random sample…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A simple random sample of size n is drawn from a population that is normally distributed. The sample mean, x, is found to be 19.6, and the sample standard deviation, s, is found to be 5.6. (a) Construct a 98% confidence interval about u if the sample size, n, is 32. (b) Construct a 98% confidence interval about µ if the sample size, n, is 58. How does increasing the sample size affect the margin of error, E? (c) Construct a 99% confidence interval about u if the sample size, n, is 32. How does increasing the level of confidence affect the size of the margin of error, E? (d) If the sample size is 21, what conditions must be satisfied to compute the confidence interval? (a) Construct a 98% confidence interval about µ if the sample size, n, is 32. Lower bound:; Upper bound: (Round to two decimal places as needed.) C...
27. Bob selects independent random samples from two populations and obtains the values î1 0.700 and p2 = 0.500. He constructs the 95% confidence interval for p1 – P2 and gets: 0.200 + 1.96(0.048) = 0.200 ± 0.094. Note that 0.048 is called the estimated standard error of pi – p2 (the ESE of the estimate). Tom wants to estimate the mean of the success rates: Pi +P2 2 (a) Calculate Tom's point estimate. (b) Given that the estimated standard er- ror of (p1 + P2)/2 is 0.024, calculate the 95% confidence interval estimate of (Pi + P2)/2. Hint: The answer has our usual form: Pt. est. +1.96 × ESE of the estimate.
A simple random sample of size n is drawn from a population that is normally distributed. The sample mean, x, is found to be 108, and the sample standard deviation, s, is found to be 10. (a) Construct a 98% confidence interval about μ if the sample size, n, is 16. (b) Construct a 98% confidence interval about µ if the sample size, n, is 12. (c) Construct a 70% confidence interval about u if the sample size, n, is 16. (d) Could we have computed the confidence intervals in parts (a)-(c) if the population had not been normally distributed? Click the icon to view the table of areas under the t-distribution. (a) Construct a 98% confidence interval about μ if the sample size, n, is 16. Lower bound:; Upper bound: (Use ascending order. Round to one decimal place as needed.)
5.STATISTICAL INFERENCE
X. is found to be 19.1, and the A simple random sample of sizen is drawn from a population that is normally distributed. The sample mean, sample standard deviation, s, is found to be 4.9. (a) Construct a 96% confidence interval about u if the sample size, n, is 39. (b) Construct a 96% confidence interval about u if the sample size, n, is 68. How does increasing the sample size affect the margin of error, E? (c) Construct a 98% confidence interval about u if the sample size, n, is 39. How does increasing the level of confidence affect the size of the margin of error, E? (d) If the sample size is 14, what conditions must be satisfied to compute the confidence interval? (a) Construct a 96% confidence interval about u if the sample size, n, is 39. Lower bound: Upper bound: (Round to two decimal places as needed.) (b) Construct a 96% confidence interval about u if the sample size, n, is 68. Lower bound: ; Upper bound: (Round to two decimal places as needed.) How does increasing the sample…
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