27. Bob-draws a simple random sample from an extremely large population of lemons. The sample size n = 700 and in the sample 250 lemons turn out to be good and 450 lemons turn out to be bad. Find the confidence interval for the population proportion p of good lemons. A. (0.30165, 0.37264) C. (0.32165, 0.39264) B. (0.31165, 0.38264) D. (0.33165, 0.40264)
27. Bob-draws a simple random sample from an extremely large population of lemons. The sample size n = 700 and in the sample 250 lemons turn out to be good and 450 lemons turn out to be bad. Find the confidence interval for the population proportion p of good lemons. A. (0.30165, 0.37264) C. (0.32165, 0.39264) B. (0.31165, 0.38264) D. (0.33165, 0.40264)
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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![**Problem 27: Confidence Interval for Lemon Quality**
Bob draws a simple random sample from an extremely large population of lemons. The sample size is \( n = 700 \), where 250 lemons are found to be good and 450 lemons are found to be bad. Determine the 95% confidence interval for the population proportion \( p \) of good lemons.
**Choices:**
A. (0.30165, 0.37264)
B. (0.31165, 0.38264)
C. (0.32165, 0.39264)
D. (0.33165, 0.40264)
**Solution Approach:**
To calculate the confidence interval, use the formula for the confidence interval for a population proportion:
\[
\hat{p} = \frac{\text{Number of good lemons}}{\text{Total sample size}} = \frac{250}{700}
\]
Next, find the standard deviation for the sample proportion:
\[
\sigma_{\hat{p}} = \sqrt{\frac{\hat{p}(1-\hat{p})}{n}}
\]
Finally, use the z-score for a 95% confidence level (approximately 1.96) to find the margin of error and construct the confidence interval:
\[
CI = \hat{p} \pm z \times \sigma_{\hat{p}}
\]
Evaluate which of the given options corresponds to the calculated interval.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F989374ce-3c35-4f4d-b4d6-005e01ca096b%2F0ca20a19-86bf-492d-ab65-b19b0dfee725%2F9klbvj2_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Problem 27: Confidence Interval for Lemon Quality**
Bob draws a simple random sample from an extremely large population of lemons. The sample size is \( n = 700 \), where 250 lemons are found to be good and 450 lemons are found to be bad. Determine the 95% confidence interval for the population proportion \( p \) of good lemons.
**Choices:**
A. (0.30165, 0.37264)
B. (0.31165, 0.38264)
C. (0.32165, 0.39264)
D. (0.33165, 0.40264)
**Solution Approach:**
To calculate the confidence interval, use the formula for the confidence interval for a population proportion:
\[
\hat{p} = \frac{\text{Number of good lemons}}{\text{Total sample size}} = \frac{250}{700}
\]
Next, find the standard deviation for the sample proportion:
\[
\sigma_{\hat{p}} = \sqrt{\frac{\hat{p}(1-\hat{p})}{n}}
\]
Finally, use the z-score for a 95% confidence level (approximately 1.96) to find the margin of error and construct the confidence interval:
\[
CI = \hat{p} \pm z \times \sigma_{\hat{p}}
\]
Evaluate which of the given options corresponds to the calculated interval.
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