27 randomly selected students were asked the number of movies they watched the previous week. The results are as follows: # of Movies 0 1 2 3 4 5 6 Frequency 3 6 5 7 2 2 2 Round all your answers to 4 decimal places where possible. The mean is: The median is: The sample standard deviation is: The first quartile is: The third quartile is: What percent of the respondents watched at least 3 movies the previous week? % 86% of all respondents watched fewer than how many movies the previous week? How would you solve this one?
27 randomly selected students were asked the number of movies they watched the previous week. The results are as follows:
| # of Movies | 0 | 1 | 2 | 3 | 4 | 5 | 6 |
|---|---|---|---|---|---|---|---|
| Frequency | 3 | 6 | 5 | 7 | 2 | 2 | 2 |
Round all your answers to 4 decimal places where possible.
The mean is:
The
The sample standard deviation is:
The first quartile is:
The third quartile is:
What percent of the respondents watched at least 3 movies the previous week? %
86% of all respondents watched fewer than how many movies the previous week?
How would you solve this one?
We have the computations as,
|
# of movies (xi) |
Frequency(fi) |
Cumulative sum |
fixi |
fixi^2 |
|
0 |
3 |
3 |
0 |
0 |
|
1 |
6 |
9 |
6 |
6 |
|
2 |
5 |
14 |
10 |
20 |
|
3 |
7 |
21 |
21 |
63 |
|
4 |
2 |
23 |
8 |
32 |
|
5 |
2 |
25 |
10 |
50 |
|
6 |
2 |
27 |
12 |
72 |
|
Sum |
27 |
|
67 |
243 |
The mean is computed as,
Thus, the mean is 2.4815.
We have,
(N + 1)/2 = (27+1)/2 = 14
The cumulative sum 14 corresponds to the value 2 of x.
Thus, the median is 2
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