26. If 5 moles of NaCl is added to a 5 liter of pure water what willbe the molality of the solution. Na-23 g/mole Cl-35.5 g/molea. 1 mc. 2 mb. 1 Md. 2 M27. If 5 moles of NaCl is added to a 5 liter of pure water what willbe the molarity of the solution.a. 1 mc.2 mb. 1 Md.2 M28. If 5 moles of NaCl is added to a 1 liter of pure water what willbe the percent by mass of the solution.a. 27.63%c. 5,85%d. 26.67%b. 29.25%29. Calculate the boiling point of a solution containing 25 gsugar (molar mass=342 g) dissolved in 150 g of water.a. 100.25 °Cc. 99.75 "Cd. 100 °Cb. 0.25 °C30. If S (s) + 02 (g) SO2 (g) have A H = -296.8 K and 280 (s) + 02(g) 2S03 (g) and A H = -798.4 kJ what will be the S (s) + 3/202 (g) S03 (g) AH =?a. -696.0 kJc. -696.0 Jd. 696.0b.696.0 kJ

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Answered: 26. If 5 moles of NaCl is added to a 5…

26. If 5 moles of NaCl is added to a 5 liter of pure water what will be the molality of the solution. Na-23 g/mole Cl-35.5 g/mole a. 1 m c. 2 m b. 1 M d. 2 M 27 1f 5 molecer)

Chemistry: An Atoms First Approach

2nd Edition

ISBN:9781305079243

Author:Steven S. Zumdahl, Susan A. Zumdahl

Publisher:Steven S. Zumdahl, Susan A. Zumdahl

Chapter10: Properties Of Solutions

Section: Chapter Questions

Problem 54E: At a certain temperature, the vapor pressure of pure benzene (C6H6) is 0.930 atm. A solution was...

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Question

26. If 5 moles of NaCl is added to a 5 liter of pure water what will
be the molality of the solution. Na-23 g/mole Cl-35.5 g/mole
a. 1 m
c. 2 m
b. 1 M
d. 2 M
27. If 5 moles of NaCl is added to a 5 liter of pure water what will
be the molarity of the solution.
a. 1 m
c.
2 m
b. 1 M
d.
2 M
28. If 5 moles of NaCl is added to a 1 liter of pure water what will
be the percent by mass of the solution.
a. 27.63%
c. 5,85%
d. 26.67%
b. 29.25%
29. Calculate the boiling point of a solution containing 25 g
sugar (molar mass=342 g) dissolved in 150 g of water.
a. 100.25 °C
c. 99.75 "C
d. 100 °C
b. 0.25 °C
30. If S (s) + 02 (g) SO2 (g) have A H = -296.8 K and 280 (s) + 02
(g) 2S03 (g) and A H = -798.4 kJ what will be the S (s) + 3/202 (g) S03 (g) AH =
?
a. -696.0 kJ
c. -696.0 J
d. 696.0
b.
696.0 kJ

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