26. Based on the graphs below, what order reaction would you say is being shown? [A] vs time In[A] vs time 1/[A] vs time. 0.20 0.15 [A]. mol T 0.05 0.00 a. 160 200 Time sec. 300 -2.0 In[A] -3.0 -4.0 -5.0 200 Time se 306 50 40 10 0 k= slope 166 200 Time sec. 308 zero order b. first order c. second order d. third order e.no order is correctly being shown
26. Based on the graphs below, what order reaction would you say is being shown? [A] vs time In[A] vs time 1/[A] vs time. 0.20 0.15 [A]. mol T 0.05 0.00 a. 160 200 Time sec. 300 -2.0 In[A] -3.0 -4.0 -5.0 200 Time se 306 50 40 10 0 k= slope 166 200 Time sec. 308 zero order b. first order c. second order d. third order e.no order is correctly being shown
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
Related questions
Question
Please provide correct explanation also.
![26. Based on the graphs below, what order reaction would you say is being shown?
[A] vs time
In[A] vs time
1/[A] vs time
0.20
0.15
[A].
mol
0.05
0.00
a.
100
3000
-2.0
In[A]
-3.0
-4.0
-5.0
100
50
200
Time sec
40
A
10
200
Time sec.
zero order b. first order c. second order d. third order e.no order is correctly being shown
0
k= slope
100
Time
200
366](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F47b0c065-d829-4cdd-bbb4-fc0ba1d88dca%2F972521c0-8c14-4dce-b5c6-1425cf5619ca%2F7bv44rh_processed.jpeg&w=3840&q=75)
Transcribed Image Text:26. Based on the graphs below, what order reaction would you say is being shown?
[A] vs time
In[A] vs time
1/[A] vs time
0.20
0.15
[A].
mol
0.05
0.00
a.
100
3000
-2.0
In[A]
-3.0
-4.0
-5.0
100
50
200
Time sec
40
A
10
200
Time sec.
zero order b. first order c. second order d. third order e.no order is correctly being shown
0
k= slope
100
Time
200
366
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