- The t-score corresponding to aone-tailed test with significancelevel of 1% and a sample size of26 is 2.787.[ Select ]- Applying a left-tailed hypothesistest on a problem with a criticalvalue of –1.782 and a teststatistic of –1.451, the nullhypothesis should be rejected.[ Select ]

For the given data Select the correct choice

Answered: 26 is 2.787. [ Select ] ▪ Applying a…

College Algebra (MindTap Course List)

12th Edition

ISBN:9781305652231

Author:R. David Gustafson, Jeff Hughes

Publisher:R. David Gustafson, Jeff Hughes

Chapter8: Sequences, Series, And Probability

Section8.7: Probability

Problem 58E: What is meant by the sample space of an experiment?

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What is meant by the sample space of an experiment?
If the chi-square statistic/value is 26.88 and the chi-square critical is 5.99, what do you do with the null hypothesis?
A student performs a test of H0: p = 0.4 versus Ha: p ≠ 0.4 and gets a p-value of 0.03. The student writes: "Because the p-value is not equal to 0.4, we reject the null hypothesis." What is wrong with the student's conclusion? Group of answer choices The p-value should be compared with a significance level such as α = 0.05, not the hypothesized value of p. The p-value should be compared with the mean, not the hypothesized value of p. The p-value should be compared with the standard deviation, not the hypothesized value of p. The student should have stated the data prove Ha is true. The student should have stated the data prove H0 is true.
For a two tailed test using z value at the .05 % significance level, we reject null hypothesis if Z is less than or equal to -1.645 if z is greater than or equal to 1.645
Suppose we wanted to construct a 90% confidence interval for a population mean based uponn = 17 randomly selected observations. Use the table to determine the appropriate value of t* to use in this case. What are the degrees of freedom and the value of t*? degrees of freedom = 16 and t* = 1.337 degrees of freedom = 16 and t* = 1.746 degrees of freedom = 17 and t* = 1.333 degrees of freedom = 17 and t* = 1.740
When 95% Confidence Intervals between means are compared, which of the following allows the null hypothesis to be accepted? That the (technical replicates) n> 10 and the error bars overlap is 1 That the (technical replicates) n = 3 and the error bars overlap is 1.5 %3D That the (biological replicates) n = 3 and the error bar overlap is 0 %3D That the (biological replicates) n = 10 and the error bar overlap is > 0.5
A new method of postoperative treatment was evaluated for patients undergoing a certain surgical procedure. Under the old method, the mean length of hospital stay was 6.3 days. The sample mean for the new method was 6.1 days. A hypothesis test was performed in which the null hypothesis stated that the mean length of stay for the new method was greater than or equal to the mean length for the old method, and the alternate hypothesis stated that the mean stay for the new method was lower. The P-value was 0.002. True or false: a) Because the P-value is very small, we can conclude that the new method provides an important reduction in the mean length of hospital stay. b) Because the P-value is very small, we can conclude that the mean length of hospital stay is less for patients treated by the new method than for patients treated by the old method.
For an ANOVA comparing three treatment conditions, what is stated by the null hypothesis (H0)? All three of the population means are different from each other. None of the other choices is correct. There are no differences between any of the population means. At least one of the three population means is different from another mean.
How did the decisions from the hypothesis ?compare to whether or not the 95% or the 99% confidence interval contained 0? Answer this question in two or three sentences.
An investigator hypothesizes that the improvement rate associated with a placebo is P1 = 0.45, and that the improvement rate associated with an active drug is P2 = 0.65. The plan is to perform a two-tailed test. Use SAS to complete each problem below. (b) How large must the sample size be if the significance level is relaxed to 0.05 and the power to 0.85? Suppose that instead of accruing an equal number of patients on each treatment arm, you allocate 1.5 patients to the new treatment for every patient on standard treatment. What sample size is required on each arm to guarantee 85% power with a level 0.05? How does the sample size computed here compare with the total required sample size in (b)?
Determine the critical value(s) for a one sample hypothesis test for proportions that has a two tailed alternative hypothesis and is using =0.02.
A potential investor conducted a 145-day survey in each of the North Mall and South Mall theaters in order to determine the difference between the average daily attendance at these two theaters. The North Mall theater averaged 634 patrons per day; while the South Mall theater averaged 597 patrons per day. From past information, it is known that the variance for North Mall is 1,076; while the variance for the South Mall is 1,329. Develop a 98% confidence interval for the difference between the average daily attendance at the two theaters. (Use North Mall – South Mall. Round your answers to the nearest whole number.) to

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26 is 2.787. [ Select ] ▪ Applying a left-tailed hypothesis test on a problem with a critical value of –1.782 and a test statistic of –1.451, the null hypothesis should be rejected. [ Select ] > >