26) A 45.0-kg sample of ice is at 0.00° C. How much heat is needed to melt it? For water LF = 334,000 J/kg and Ly= 2.256 x 106 J/kg. A) 0.00 kJ B) 1.02 x 105 kJ C) 1.50 × 104 kJ D) 4.10 x 106 kJ

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Please show all calculations and type them out since I have bad eyesight and it is very difficult for me to read handwriting 

**Heat Calculation for Melting Ice**

**Problem Statement:**
A 45.0-kg sample of ice is at 0.00°C. How much heat is needed to melt it?

Given data:
- The latent heat of fusion for water (L_F) = 334,000 J/kg
- The latent heat of vaporization for water (L_V) = 2.256 × 10^6 J/kg

Options to select from:
A) 0.00 kJ
B) 1.02 × 10^5 kJ
C) 1.50 × 10^4 kJ
D) 4.10 × 10^6 kJ
Transcribed Image Text:**Heat Calculation for Melting Ice** **Problem Statement:** A 45.0-kg sample of ice is at 0.00°C. How much heat is needed to melt it? Given data: - The latent heat of fusion for water (L_F) = 334,000 J/kg - The latent heat of vaporization for water (L_V) = 2.256 × 10^6 J/kg Options to select from: A) 0.00 kJ B) 1.02 × 10^5 kJ C) 1.50 × 10^4 kJ D) 4.10 × 10^6 kJ
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