2:58T00 23 == | CH 17, 1EP a. Step 1/8 The main objective is to show that 0 -{(5) с or not. Step 2/8 | b,c,de R (R, +, .) Recall that multiplication are closed. is a subring of { * b 0 A = 1- (0₂5). B = ( ) = S C d " Let can be proved as follows. .25% ال... (0) is a Ring so, addition and < M₂ (R) then the result
2:58T00 23 == | CH 17, 1EP a. Step 1/8 The main objective is to show that 0 -{(5) с or not. Step 2/8 | b,c,de R (R, +, .) Recall that multiplication are closed. is a subring of { * b 0 A = 1- (0₂5). B = ( ) = S C d " Let can be proved as follows. .25% ال... (0) is a Ring so, addition and < M₂ (R) then the result
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter4: Polynomial And Rational Functions
Section4.3: Zeros Of Polynomials
Problem 32E
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Question
Why is it A-B. Isn't it A+B, since it is closes under addition. Please explain
Transcribed Image Text:2:58
a.
Step 1/8
CH 17, 1EP
Step 2/8
The main objective is to show that
b
s={(0₂5)
| b,c,de R
or not.
T
QO ●
AB =
Recall that
multiplication are closed.
(R, +,-)
0 e
A
1=(0 $).B=(º c) ES
g
Let
can be proved as follows.
Thus,
subring of
210
It can seen that
(b.f
b.g
(d⋅f c.e+d.g).
|||
If b, f #0, then AB & S.
is a Ring so, addition and
A-B=
is a subring of
0
=(cºs
M₂ (R)
s={(5) where h.c.de R}
S=
b,c,d
{ | 25%
M₂ (R)
b-e
c-f d-g) and
then the result
(0)
is not a
<
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