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253-45-8 (5²-5) (5²+4) 253-15-8 s(5-1)(5²+4) Focusing on 5(5-1) (5²+4) A+B (3-1) S on denominator + C₂ +D Cş 5²74

253-45-8 (5²-5) (5²+4) 253-15-8 s(5-1)(5²+4) Focusing on 5(5-1) (5²+4) A+B (3-1) S on denominator + C₂ +D Cş 5²74

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Indeed help finding C & D in this partial fraction expansion.
Example 7: Complex Roots 253-45-8 (5²-5) (5²+4) 253-15-8 s(5-1) (5²+4) = -8= - 4A A=2 Focusing on s(5-1) ( 5+4) A+B (3-1) S denominator write this + C₂ +D way when complex Sz+l 253-45-8= A (S-1) (5²+4) +B(S) (5²+4) + ((S+D) (5) (5-1) S=0 2 (0)³ - 4(0)-8= A(0-1) (0²+4) +B(0)</0²+1) + (((0) + D) (0) (0-1) -8= A (-1) (4) 5 = 1 2 (1) ³-4(1)-8= 2 (171) (1²+4) + B (1)(1² +4). 4) + [CCD+D] (BCI-D 2-4-8= B(1) (5) -10= 5B B=-2
Transcribed Image Text:Example 7: Complex Roots 253-45-8 (5²-5) (5²+4) 253-15-8 s(5-1) (5²+4) = -8= - 4A A=2 Focusing on s(5-1) ( 5+4) A+B (3-1) S denominator write this + C₂ +D way when complex Sz+l 253-45-8= A (S-1) (5²+4) +B(S) (5²+4) + ((S+D) (5) (5-1) S=0 2 (0)³ - 4(0)-8= A(0-1) (0²+4) +B(0)</0²+1) + (((0) + D) (0) (0-1) -8= A (-1) (4) 5 = 1 2 (1) ³-4(1)-8= 2 (171) (1²+4) + B (1)(1² +4). 4) + [CCD+D] (BCI-D 2-4-8= B(1) (5) -10= 5B B=-2
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