Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Indeed help finding C & D in this partial fraction expansion.
![Example 7: Complex Roots
253-45-8
(5²-5) (5²+4)
253-15-8
s(5-1) (5²+4)
=
-8= - 4A
A=2
Focusing on
s(5-1) ( 5+4)
A+B
(3-1)
S
denominator
write this
+ C₂ +D way when
complex
Sz+l
253-45-8= A (S-1) (5²+4) +B(S) (5²+4) + ((S+D) (5) (5-1)
S=0
2 (0)³ - 4(0)-8= A(0-1) (0²+4) +B(0)</0²+1) + (((0) + D) (0) (0-1)
-8= A (-1) (4)
5 = 1
2 (1) ³-4(1)-8= 2 (171) (1²+4) + B (1)(1² +4).
4) + [CCD+D] (BCI-D
2-4-8= B(1) (5)
-10= 5B
B=-2](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F5362cbea-9427-4b2b-99cb-57a208edd853%2F1b12df5e-9fbd-42c2-8ba6-a25dc52c0785%2F4ied26_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Example 7: Complex Roots
253-45-8
(5²-5) (5²+4)
253-15-8
s(5-1) (5²+4)
=
-8= - 4A
A=2
Focusing on
s(5-1) ( 5+4)
A+B
(3-1)
S
denominator
write this
+ C₂ +D way when
complex
Sz+l
253-45-8= A (S-1) (5²+4) +B(S) (5²+4) + ((S+D) (5) (5-1)
S=0
2 (0)³ - 4(0)-8= A(0-1) (0²+4) +B(0)</0²+1) + (((0) + D) (0) (0-1)
-8= A (-1) (4)
5 = 1
2 (1) ³-4(1)-8= 2 (171) (1²+4) + B (1)(1² +4).
4) + [CCD+D] (BCI-D
2-4-8= B(1) (5)
-10= 5B
B=-2
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