25. From your textbook, find the values for the enthalpy of formation (AHof) for CaCO3(s), CaO(s), and CO2(g). Determine the enthalpy of reaction for the decomposition of CaCO3 using the following equation: AH°TXN = E(AHOf(products)-EAHof(reactants) The enthalpy formation of CaCO3 =-1207.6kJ/mol The enthalpy formation of CaO- -634.9kJ/mol The enthalpy formation of CO2 = -393.5kJ/mol AH°rxn =
Thermochemistry
Thermochemistry can be considered as a branch of thermodynamics that deals with the connections between warmth, work, and various types of energy, formed because of different synthetic and actual cycles. Thermochemistry describes the energy changes that occur as a result of reactions or chemical changes in a substance.
Exergonic Reaction
The term exergonic is derived from the Greek word in which ‘ergon’ means work and exergonic means ‘work outside’. Exergonic reactions releases work energy. Exergonic reactions are different from exothermic reactions, the one that releases only heat energy during the course of the reaction. So, exothermic reaction is one type of exergonic reaction. Exergonic reaction releases work energy in different forms like heat, light or sound. For example, a glow stick releases light making that an exergonic reaction and not an exothermic reaction since no heat is released. Even endothermic reactions at very high temperature are exergonic.
How do I determine the enthalpy of reaction for the decomposition of CaCO3?
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![25. From your textbook, find the values for the enthalpy of formation (AHof) for CaCO3(s),
CaO(s), and CO2(g). Determine the enthalpy of reaction for the decomposition of CaCO3
using the following equation:
AH°rxn = E(AHOf(products)-EAHof(reactants)
%3D
The enthalpy formation of CaCO3 =-1207.6kJ/mol
The enthalpy formation of CaO= -634.9kJ/mol
The enthalpy formation of CO2 = -393.5kJ/mol
AH°rxn =](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe3253152-6f2e-4963-96b1-4e13d7f041f9%2Fa0c81cf9-eaab-4bb0-af64-581d59dbf56e%2Fn4n6tkf_processed.jpeg&w=3840&q=75)
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