25. Describe {x : x² + 2x < 3} as an interval. Hint: Plot y = x² + 2x – 3. SOLUTION The inequality x2 + 2x < 3 is equivalent to x2 + 2x – 3 < 0. The graph of y = x2 + 2x – 3 is shown below. From this graph, it follows that x² + 2x – 3 < 0 for –3 < x < 1. Thus, the set {x : x? + 2x < 3} is equivalent to the interval (-3, 1). y -x+ 2x – 3 12 10-
25. Describe {x : x² + 2x < 3} as an interval. Hint: Plot y = x² + 2x – 3. SOLUTION The inequality x2 + 2x < 3 is equivalent to x2 + 2x – 3 < 0. The graph of y = x2 + 2x – 3 is shown below. From this graph, it follows that x² + 2x – 3 < 0 for –3 < x < 1. Thus, the set {x : x? + 2x < 3} is equivalent to the interval (-3, 1). y -x+ 2x – 3 12 10-
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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