25. a. Show that if A has a row of zeros and B is any matrix for which AB is defined, then AB also has a row of zeros. b. Find a similar result involving a column of zeros. 26. In each part, find a 6 × 6 matrix [a] that satisfies the stated condition. Make your answers as general as possible by using letters rather than specific numbers for the nonzero entries. a. aij = 0 if if i #j ij if |i-j|>1

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### Matrix Problems and Solutions

#### 25. Matrix Operations with Rows and Columns of Zeros

**a. Show that if \(A\) has a row of zeros and \(B\) is any matrix for which \(AB\) is defined, then \(AB\) also has a row of zeros.**

To demonstrate this, consider:
- \(A\) as an \(m \times n\) matrix.
- \(B\) as an \(n \times p\) matrix.
Assume the \(i\)th row of \(A\) is a row of zeros, i.e., \(\mathbf{a}_i = [0, 0, \ldots, 0]\). Then the \(i\)th row of the product \(AB\) is given by \(\mathbf{a}_i B = [0, 0, \ldots, 0] B = [0, 0, \ldots, 0]\). Therefore, the \(i\)th row of \(AB\) is a row of zeros.

**b. Find a similar result involving a column of zeros.**

Consider:
- \(A\) as an \(m \times n\) matrix.
- \(B\) as an \(n \times p\) matrix.
Assume the \(j\)th column of \(B\) is a column of zeros, i.e., \(\mathbf{b}_j = [0, 0, \ldots, 0]^T\). Then the product of \(A\) with the \(j\)th column of \(B\) results in the \(j\)th column of \(AB\) being a column of zeros, because:

\[ 
AB = [A\mathbf{b}_1, A\mathbf{b}_2, \ldots, A\mathbf{b}_p] 
\]

where each \(\mathbf{b}_k\) is a column vector. If \(\mathbf{b}_j = [0, 0, \ldots, 0]^T\), then \(A \mathbf{b}_j = [0, 0, \ldots, 0]^T\), contributing a zero column to \(AB\).

#### 26. Constructing a \(6 \times 6\) Matrix with Specific Conditions

**In each part, find
Transcribed Image Text:### Matrix Problems and Solutions #### 25. Matrix Operations with Rows and Columns of Zeros **a. Show that if \(A\) has a row of zeros and \(B\) is any matrix for which \(AB\) is defined, then \(AB\) also has a row of zeros.** To demonstrate this, consider: - \(A\) as an \(m \times n\) matrix. - \(B\) as an \(n \times p\) matrix. Assume the \(i\)th row of \(A\) is a row of zeros, i.e., \(\mathbf{a}_i = [0, 0, \ldots, 0]\). Then the \(i\)th row of the product \(AB\) is given by \(\mathbf{a}_i B = [0, 0, \ldots, 0] B = [0, 0, \ldots, 0]\). Therefore, the \(i\)th row of \(AB\) is a row of zeros. **b. Find a similar result involving a column of zeros.** Consider: - \(A\) as an \(m \times n\) matrix. - \(B\) as an \(n \times p\) matrix. Assume the \(j\)th column of \(B\) is a column of zeros, i.e., \(\mathbf{b}_j = [0, 0, \ldots, 0]^T\). Then the product of \(A\) with the \(j\)th column of \(B\) results in the \(j\)th column of \(AB\) being a column of zeros, because: \[ AB = [A\mathbf{b}_1, A\mathbf{b}_2, \ldots, A\mathbf{b}_p] \] where each \(\mathbf{b}_k\) is a column vector. If \(\mathbf{b}_j = [0, 0, \ldots, 0]^T\), then \(A \mathbf{b}_j = [0, 0, \ldots, 0]^T\), contributing a zero column to \(AB\). #### 26. Constructing a \(6 \times 6\) Matrix with Specific Conditions **In each part, find
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