25. A proton is accelerated by a potential difference of 7.20 x 10² v. What is the change in kinetic energy of the proton? [1.15 x 10 16 J]
25. A proton is accelerated by a potential difference of 7.20 x 10² v. What is the change in kinetic energy of the proton? [1.15 x 10 16 J]
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![25. A proton is accelerated by a potential difference of 7.20 x 10? V. What is the change in kinetic energy of
the proton? [1.15 x 1016 J]
26. An alpha particle gains 1.50 x 1015 J of kinetic energy. Through what potential difference was it
accelerated? [4.69 x 10³ V]
27. The electric field strength between two parallel plates is 9.3 x 10² v/m when the plates are 7.0 cm
apart. What would the electric field strength be if the plates were 5.0 cm apart? [1.3 x 103 V/m]
28. An electron is released from rest adjacent to the negative plate in a parallel plate apparatus. A
potential difference of 500 V is maintained between the plates, and they are in a vacuum. With what
speed does the electron collide with the positive plate? (1.3 x 10? m/s)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8cfb9dfa-3a7e-4354-9c64-0dd8c9eaa7b9%2Fa335d6b8-a476-4e32-a469-5e7a97465380%2Faqh8h56_processed.png&w=3840&q=75)
Transcribed Image Text:25. A proton is accelerated by a potential difference of 7.20 x 10? V. What is the change in kinetic energy of
the proton? [1.15 x 1016 J]
26. An alpha particle gains 1.50 x 1015 J of kinetic energy. Through what potential difference was it
accelerated? [4.69 x 10³ V]
27. The electric field strength between two parallel plates is 9.3 x 10² v/m when the plates are 7.0 cm
apart. What would the electric field strength be if the plates were 5.0 cm apart? [1.3 x 103 V/m]
28. An electron is released from rest adjacent to the negative plate in a parallel plate apparatus. A
potential difference of 500 V is maintained between the plates, and they are in a vacuum. With what
speed does the electron collide with the positive plate? (1.3 x 10? m/s)
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