25) To find the missing angle below, would you use the Law of Sines or Law of Cosines. Find the missing angle. 7 in. 10 in. с B C. Law of Sines,

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### Mathematics: Introduction to the Law of Sines and Law of Cosines

**Example Problem:**

To find the missing angle below, would you use the Law of Sines or Law of Cosines? Find the missing angle.

#### Triangle ABC 

- **Angle A** = 112°
- **Side a (opposite to angle A)** = 7 in
- **Side c (opposite to angle C)** = 10 in

#### Provided Options:

A. Law of Cosines, ∠B = 43.5°

B. Law of Sines, ∠B = 40.5°

C. Law of Sines, ∠B = 60.5°

D. Law of Cosines, ∠B = 45.5°

The diagrams shows a triangle with vertices labeled A, B, and C. Angle A is marked as 112 degrees, side opposite to A (side BC) is 7 inches, and another side opposite to some angle is 10 inches.

Among the given options, choice B is marked as correct. Therefore, the missing angle B = 40.5° can be found using the Law of Sines.

**Detailed Explanation:**

The Law of Sines and Law of Cosines are two important tools in trigonometry for solving triangles, especially non-right triangles.

- **Law of Sines**: Used when we know either two angles and one side or two sides and a non-included angle.
  \[
  \frac{a}{\sin(A)} = \frac{b}{\sin(B)} = \frac{c}{\sin(C)}
  \]

- **Law of Cosines**: Used when we know either three sides or two sides and the included angle.
  \[
  c^2 = a^2 + b^2 - 2ab \cdot \cos(C)
  \]

In this problem, we are given two sides and a non-included angle, which suggests using the Law of Sines.

- **Given**: Angle A = 112°, side opposite to A (a) = 7 in, side opposite to C (c) = 10 in.
- **Required**: Angle B.

Using the Law of Sines:
  \[
  \frac{a}{\sin(A)} = \frac{b}{\sin(B)}
  \]

Substituting the given values:
Transcribed Image Text:### Mathematics: Introduction to the Law of Sines and Law of Cosines **Example Problem:** To find the missing angle below, would you use the Law of Sines or Law of Cosines? Find the missing angle. #### Triangle ABC - **Angle A** = 112° - **Side a (opposite to angle A)** = 7 in - **Side c (opposite to angle C)** = 10 in #### Provided Options: A. Law of Cosines, ∠B = 43.5° B. Law of Sines, ∠B = 40.5° C. Law of Sines, ∠B = 60.5° D. Law of Cosines, ∠B = 45.5° The diagrams shows a triangle with vertices labeled A, B, and C. Angle A is marked as 112 degrees, side opposite to A (side BC) is 7 inches, and another side opposite to some angle is 10 inches. Among the given options, choice B is marked as correct. Therefore, the missing angle B = 40.5° can be found using the Law of Sines. **Detailed Explanation:** The Law of Sines and Law of Cosines are two important tools in trigonometry for solving triangles, especially non-right triangles. - **Law of Sines**: Used when we know either two angles and one side or two sides and a non-included angle. \[ \frac{a}{\sin(A)} = \frac{b}{\sin(B)} = \frac{c}{\sin(C)} \] - **Law of Cosines**: Used when we know either three sides or two sides and the included angle. \[ c^2 = a^2 + b^2 - 2ab \cdot \cos(C) \] In this problem, we are given two sides and a non-included angle, which suggests using the Law of Sines. - **Given**: Angle A = 112°, side opposite to A (a) = 7 in, side opposite to C (c) = 10 in. - **Required**: Angle B. Using the Law of Sines: \[ \frac{a}{\sin(A)} = \frac{b}{\sin(B)} \] Substituting the given values:
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