25 substarce D1toF(KS/mel) G(KJ(mcl) s°(SImel.Kl) P2 PC13 g POCsg Clay 144.3 -2881 -542.2 218.1 311.7 325 222.96 20s.0 69.91 -285.83 The value of AS° for the formation of phespherustvichleride Fromits censtinuent element P2 (g)t 3C12 (9) → 2 PCl 3cg) Fs- 9/ Komel A)-311.7 B) +311.7'C)-263.6Dti29.4E) -/29.4 100

Chemistry
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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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**Thermodynamic Properties Table**

The table below provides standard thermodynamic data for several substances in their gaseous forms. The values are presented for standard enthalpy of formation (\( \Delta H^\circ_f \)), standard Gibbs free energy (\( G^\circ \)), and standard entropy (\( S^\circ \)). All values are specific to each substance in the units indicated.

| **Substance** | \( \Delta H^\circ_f \) (kJ/mol) | \( G^\circ \) (kJ/mol) | \( S^\circ \) (J/mol·K) |
|---------------|------------------|--------------|----------------|
| \( P_2 \) (g) | 144.3            | -            | 218.1          |
| \( PCl_3 \) (g)| -288.1          | -            | 311.7          |
| \( POCl_3 \) (g)| -542.2          | -            | 325            |
| \( Cl_2 \) (g)| 0                | 0            | 222.96         |
| \( O_2 \) (g) | 0                | 0            | 205.0          |
| \( I_2O_4 \) | -285.83         | -            | 69.91          |

**Entropy Change Calculation**

The problem provided is to calculate the entropy change (\( \Delta S^\circ \)) for the formation of phosphorus trichloride (\( PCl_3 \)) from its constituent elements according to the reaction:

\[ P_2 (g) + 3Cl_2 (g) \rightarrow 2PCl_3 (g) \]

The possible answers for \( \Delta S^\circ \) (J/K·mol) are:
- A) -311.7
- B) +311.7
- C) -263.6
- D) (+129.4) E) -129.4

**Instructions**

To solve this type of problem, you can use the standard entropy values and apply the formula for calculating the change in entropy of the reaction:

\[ \Delta S^\circ = \sum S^\circ_{products} - \sum S^\circ_{reactants} \]

Use the entropy values provided in the table for the necessary calculations.
Transcribed Image Text:**Thermodynamic Properties Table** The table below provides standard thermodynamic data for several substances in their gaseous forms. The values are presented for standard enthalpy of formation (\( \Delta H^\circ_f \)), standard Gibbs free energy (\( G^\circ \)), and standard entropy (\( S^\circ \)). All values are specific to each substance in the units indicated. | **Substance** | \( \Delta H^\circ_f \) (kJ/mol) | \( G^\circ \) (kJ/mol) | \( S^\circ \) (J/mol·K) | |---------------|------------------|--------------|----------------| | \( P_2 \) (g) | 144.3 | - | 218.1 | | \( PCl_3 \) (g)| -288.1 | - | 311.7 | | \( POCl_3 \) (g)| -542.2 | - | 325 | | \( Cl_2 \) (g)| 0 | 0 | 222.96 | | \( O_2 \) (g) | 0 | 0 | 205.0 | | \( I_2O_4 \) | -285.83 | - | 69.91 | **Entropy Change Calculation** The problem provided is to calculate the entropy change (\( \Delta S^\circ \)) for the formation of phosphorus trichloride (\( PCl_3 \)) from its constituent elements according to the reaction: \[ P_2 (g) + 3Cl_2 (g) \rightarrow 2PCl_3 (g) \] The possible answers for \( \Delta S^\circ \) (J/K·mol) are: - A) -311.7 - B) +311.7 - C) -263.6 - D) (+129.4) E) -129.4 **Instructions** To solve this type of problem, you can use the standard entropy values and apply the formula for calculating the change in entropy of the reaction: \[ \Delta S^\circ = \sum S^\circ_{products} - \sum S^\circ_{reactants} \] Use the entropy values provided in the table for the necessary calculations.
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