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9. f(-5) = (5)²-19 = 25 -19 -6 b. lim x²-19 X→-5 = (-5)² -19 = 25-19 = 6 с C f(-5) = lim f(x) X-7-5 6 = 6 =

9. f(-5) = (5)²-19 = 25 -19 -6 b. lim x²-19 X→-5 = (-5)² -19 = 25-19 = 6 с C f(-5) = lim f(x) X-7-5 6 = 6 =

Intermediate Algebra
Intermediate Algebra
10th Edition
ISBN:9781285195728
Author:Jerome E. Kaufmann, Karen L. Schwitters
Publisher:Jerome E. Kaufmann, Karen L. Schwitters
Chapter9: Functions
Section9.S: Summary
Problem 3S
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using an online graphing app, construct a graph which lie on the interval (-8,8)

choose three different intervals

prove that those intervals are continuous using the conditions a,b,c in the picture

(-5,5) 14(x)=x²-19 9. f(-5) = (5) ²-19 = 25 -19 b. lim x²-19 X→-5 = (-5)² -19 = 25-19 C f(-5) = lim f(x) X-7-5 6 = 6 ما = ما -
Transcribed Image Text:(-5,5) 14(x)=x²-19 9. f(-5) = (5) ²-19 = 25 -19 b. lim x²-19 X→-5 = (-5)² -19 = 25-19 C f(-5) = lim f(x) X-7-5 6 = 6 ما = ما -
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