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25 1. ƒ x²√5 − x²dx = − ²x(5 − x²) (5 − 2x²) + ²5 Arcsin (5x) + C 2009

25 1. ƒ x²√5 − x²dx = − ²x(5 − x²) (5 − 2x²) + ²5 Arcsin (5x) + C 2009

College Algebra
College Algebra
10th Edition
ISBN:9781337282291
Author:Ron Larson
Publisher:Ron Larson
ChapterA: Errors And The Algebra Of Calculus
Section: Chapter Questions
Problem 5ECP
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25 1. fx²³√5-x²dx = -x(5-x²)=(5-2x²) + Arcsin (x) + c 8
Transcribed Image Text:25 1. fx²³√5-x²dx = -x(5-x²)=(5-2x²) + Arcsin (x) + c 8
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