24. Initially, a tank contains 400 L of water with 10 kg of salt in solution. Water containing 0.1 kg of salt per liter (L) is entering at a rate of 1 L/min, and the mixture is allowed to flow out of the tank at a rate of 2 L/min. Let Q(t) be the amount of salt at time t measured in kilograms. What is the right formulation of the differential equation for Q(t)? 2Q(t) O dQ = 0.1 dt - 400 + t dQ 2Q(t) = 0.1 dt 400 – t O dQ 10 2Q(t) - dt 400 400 +t O dQ = 0.1 2Q(t) dt 400 O dQ 0.1 2Q(t) dt 400 400 – t -

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24. Initially, a tank contains 400 L of water with 10 kg of salt in solution. Water containing
0.1 kg of salt per liter (L) is entering at a rate of 1 L/min, and the mixture is allowed
to flow out of the tank at a rate of 2 L/min. Let Q(t) be the amount of salt at time
t measured in kilograms. What is the right formulation of the differential equation for
Q(t)?
O dQ
2Q(t)
0.1
dt
400 + t
O dQ
= 0.1
2Q(t)
dt
400 – t
-
dQ
10
2Q(t)
dt
400
400 +t
dQ
2Q(t)
= 0.1
-
dt
400
2Q(t)
400 – t
O dQ
0.1
dt
400
-
Transcribed Image Text:24. Initially, a tank contains 400 L of water with 10 kg of salt in solution. Water containing 0.1 kg of salt per liter (L) is entering at a rate of 1 L/min, and the mixture is allowed to flow out of the tank at a rate of 2 L/min. Let Q(t) be the amount of salt at time t measured in kilograms. What is the right formulation of the differential equation for Q(t)? O dQ 2Q(t) 0.1 dt 400 + t O dQ = 0.1 2Q(t) dt 400 – t - dQ 10 2Q(t) dt 400 400 +t dQ 2Q(t) = 0.1 - dt 400 2Q(t) 400 – t O dQ 0.1 dt 400 -
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