24. (1 − xy)−² dx + [y² + x²(1 − xy)¯²] dy = 0; when x = = 1. 4, y = ANS. xy4y³ + 3xy - 3x − 3 = 0. 6xy²2y) dy = 0; when x = : 0, y = 2. ANS. 25. (yexy - 2y³) dx + (x exy - exy = 2xy³ + y² - 3. 26. (3 + y + 2y² sin² x) dx + (x + 2xy − y sin 2x) dy : 0. ANS. y² sin 2x = c + 2x(3 + y + y²). 27. 2x[3x + y - y exp(-x²)] dx + [x² + 3y² + exp(-x²)] dy 0. ANS. x²y + y³ + 2x³ + y exp(-x²) = c. 28. (xy² + x - 2y + 3) dx + x²y dy = 2(x + y) dy; when x = 1, y = 1. ANS. (xy - 2)² + (x + 3)² = 2y² + 15. |||
24. (1 − xy)−² dx + [y² + x²(1 − xy)¯²] dy = 0; when x = = 1. 4, y = ANS. xy4y³ + 3xy - 3x − 3 = 0. 6xy²2y) dy = 0; when x = : 0, y = 2. ANS. 25. (yexy - 2y³) dx + (x exy - exy = 2xy³ + y² - 3. 26. (3 + y + 2y² sin² x) dx + (x + 2xy − y sin 2x) dy : 0. ANS. y² sin 2x = c + 2x(3 + y + y²). 27. 2x[3x + y - y exp(-x²)] dx + [x² + 3y² + exp(-x²)] dy 0. ANS. x²y + y³ + 2x³ + y exp(-x²) = c. 28. (xy² + x - 2y + 3) dx + x²y dy = 2(x + y) dy; when x = 1, y = 1. ANS. (xy - 2)² + (x + 3)² = 2y² + 15. |||
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Topic: Exact DE
please answer number 27
![= 1.
24. (1 − xy)−² dx + [y² + x²(1 − xy)¯²] dy = 0; when x = 4, y =
ANS. xy4y³ + 3xy − 3x − 3 = 0.
-
25. (ye*v – 2y³) dx + (x e*³ − 6xy² – 2y) dy = 0; when x = 0, y = 2.
ANS. exy = 2xy³ + y² – 3.
26. (3 + y + 2y² sin² x) dx + (x + 2xy − y sin 2x) dy = 0.
ANS. y² sin 2x = c + 2x(3 + y + y²).
27. 2x[3x + y − y exp (−x²)] dx + [x² + 3y² + exp(-x²)] dy = 0.
28. (xy² + x - 2y + 3) dx + x²y dy = 2(x + y) dy; when x
ANS. (xy — 2)² + (x + 3)² = 2y² + 15.
ANS. x²y + y² + 2x³ + y exp (− x²) = c.
1, y = 1.
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Transcribed Image Text:= 1.
24. (1 − xy)−² dx + [y² + x²(1 − xy)¯²] dy = 0; when x = 4, y =
ANS. xy4y³ + 3xy − 3x − 3 = 0.
-
25. (ye*v – 2y³) dx + (x e*³ − 6xy² – 2y) dy = 0; when x = 0, y = 2.
ANS. exy = 2xy³ + y² – 3.
26. (3 + y + 2y² sin² x) dx + (x + 2xy − y sin 2x) dy = 0.
ANS. y² sin 2x = c + 2x(3 + y + y²).
27. 2x[3x + y − y exp (−x²)] dx + [x² + 3y² + exp(-x²)] dy = 0.
28. (xy² + x - 2y + 3) dx + x²y dy = 2(x + y) dy; when x
ANS. (xy — 2)² + (x + 3)² = 2y² + 15.
ANS. x²y + y² + 2x³ + y exp (− x²) = c.
1, y = 1.
=
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