24 lim b7b+1 lim t 5 Calculate the following limits by direct substitution. (b-4)² (1 – t) (t + 5) 3t - 7 lim (6y) (y² + 1)³ -1 lim √3(x² + 12) = z 0 lin t> 6 ² + 3t - = lim y³ (5-3y²) 2 2 = = = 3

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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24
lim
b +7 b + 1
lim
t 5
Calculate the following limits by direct substitution.
(b-4)²
(1
t)(t + 5)
3t - 7
lim (6 - y) (y² + 1)³ :
y-1
lim√√3(x² + 12) =
lim (√² + 3t-2)
t6
=
lim y³ (5 - 3y²) =
V2
Transcribed Image Text:24 lim b +7 b + 1 lim t 5 Calculate the following limits by direct substitution. (b-4)² (1 t)(t + 5) 3t - 7 lim (6 - y) (y² + 1)³ : y-1 lim√√3(x² + 12) = lim (√² + 3t-2) t6 = lim y³ (5 - 3y²) = V2
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