234Th + He 90 234 Pa + e 91 Be+ e 222Rn+ He 86 a. 238 92 Uranium b. 226 88 Radium c. 73 Lithium d. 234 90 Thorium
234Th + He 90 234 Pa + e 91 Be+ e 222Rn+ He 86 a. 238 92 Uranium b. 226 88 Radium c. 73 Lithium d. 234 90 Thorium
Related questions
Question
![On this page, we are exploring nuclear reactions and decay series. Pay special attention to how elements transmute into other elements through different types of particles being emitted or absorbed. Consider the following reactions and match them with the given element options:
1. **\[ _{90}^{234}Th + _{2}^{4}He \]**
2. **\[ _{91}^{234}Pa + _{0}^{0}e \]**
3. **\[ _{4}^{7}Be + _{-1}^{0}e \]**
4. **\[ _{86}^{222}Rn + _{2}^{4}He \]**
Here are the options you should match each reaction to:
a. **\[ _{92}^{238}U \]** (238 92 Uranium)
b. **\[ _{88}^{226}Ra \]** (226 88 Radium)
c. **\[ _{3}^{7}Li \]** (7 3 Lithium)
d. **\[ _{90}^{234}Th \]** (234 90 Thorium)
By analyzing the reactions, you can determine how each of the given elements transforms through emission or absorption of particles such as alpha particles (\[_{2}^{4}He\]) or electrons (\[_{0}^{0}e\] or \[_{-1}^{0}e\]).
**Explanation of Reactions and Their Matches:**
1. **\[ _{90}^{234}Th + _{2}^{4}He \]**
- This reaction depicts the emission of an alpha particle, transforming Thorium-234.
- **Likely Match:** d. 234 90 Thorium
2. **\[ _{91}^{234}Pa + _{0}^{0}e \]**
- This reaction involves an electron, indicating beta decay of Protactinium-234.
- **Likely Match:** No exact match available in the given options.
3. **\[ _{4}^{7}Be + _{-1}^{0}e \]**
- This reaction shows the capture of an electron by Beryllium-7.
- **Likely Match:** c. 7 3 Lithium
4. **\[ _{86}^{222}Rn + _{2}^{4}He \]**
- This represents the emission of an alpha particle](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F749cbf17-77bf-45bf-b7c3-9b7458118f86%2F5efd0eda-8a25-4201-a898-a2a3b74d13c9%2Fu6dqjvt_processed.png&w=3840&q=75)
Transcribed Image Text:On this page, we are exploring nuclear reactions and decay series. Pay special attention to how elements transmute into other elements through different types of particles being emitted or absorbed. Consider the following reactions and match them with the given element options:
1. **\[ _{90}^{234}Th + _{2}^{4}He \]**
2. **\[ _{91}^{234}Pa + _{0}^{0}e \]**
3. **\[ _{4}^{7}Be + _{-1}^{0}e \]**
4. **\[ _{86}^{222}Rn + _{2}^{4}He \]**
Here are the options you should match each reaction to:
a. **\[ _{92}^{238}U \]** (238 92 Uranium)
b. **\[ _{88}^{226}Ra \]** (226 88 Radium)
c. **\[ _{3}^{7}Li \]** (7 3 Lithium)
d. **\[ _{90}^{234}Th \]** (234 90 Thorium)
By analyzing the reactions, you can determine how each of the given elements transforms through emission or absorption of particles such as alpha particles (\[_{2}^{4}He\]) or electrons (\[_{0}^{0}e\] or \[_{-1}^{0}e\]).
**Explanation of Reactions and Their Matches:**
1. **\[ _{90}^{234}Th + _{2}^{4}He \]**
- This reaction depicts the emission of an alpha particle, transforming Thorium-234.
- **Likely Match:** d. 234 90 Thorium
2. **\[ _{91}^{234}Pa + _{0}^{0}e \]**
- This reaction involves an electron, indicating beta decay of Protactinium-234.
- **Likely Match:** No exact match available in the given options.
3. **\[ _{4}^{7}Be + _{-1}^{0}e \]**
- This reaction shows the capture of an electron by Beryllium-7.
- **Likely Match:** c. 7 3 Lithium
4. **\[ _{86}^{222}Rn + _{2}^{4}He \]**
- This represents the emission of an alpha particle
Expert Solution
![](/static/compass_v2/shared-icons/check-mark.png)
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
Step by step
Solved in 3 steps with 3 images
![Blurred answer](/static/compass_v2/solution-images/blurred-answer.jpg)