23 A company claims that the mean monthly residential electricity consumption in a certain region is more than 890 kilowatt-hours (kWh). You want to test this claim. You find that a random sample of 62 residential customers has a mean monthly consumption of 920 kWh. Assume the population standard deviation is 126 kWh. At a = 0.01, can you support the claim? Complete parts (a) through (e).(a) Identify H, and H. Choose the correct answer below.O A. Ho HS 920H> 920 (claim)OB. H: >890 (claim)H:uS B90О с. Но: и920OD. Hg: > 920 (claim)Hg:H 920 (claim)Hạ: us 920OE. H: us890H3:H> 890 (claim)OF. H: =890 (claim)Ha: u 890(b) Find the critical value(s) and identify the rejection region(s). Select the correct choice below and fill in the answer box within your choice. Use technology.(Round to two decimal places as needed.)O A. The critical values are tO B. The critical value is.Identify the rejection region(s). Select the correct choice below.O A. The reiection regions are z<-2,33 and z> 2.33.O B. The rejection region is z> 2.33.O C. The rejection region is z<2.33.(c) Find the standardized test statistic. Use technology.The standardized test statistic is z=(Round to two decimal placesneeded."(d) Decide whether to reject or fail to reject the null hypothesis.O A. Fail to reject H, because the standardized test statistic is not in the rejection region.O B. Reject H, because the standardized test statistic is in the rejection region.O C. Fail to reject Ho because the standardized test statistic is in the rejection region.O D. Reject H,, because the standardized test statistic is not in the rejection region.(e) Interpret the decision in the context of the original claim.At the 1% significance level, there enough evidence toV the claim that the mean monthly residential electricity consumption in a certain regionO kWh.

Name: 23 A company claims that the mean monthly residential electricity cons
Uploaded: 2024-03-20T07:06:41.000Z
Channel: Bartleby
Description: 23 A company claims that the mean monthly residential electricity consumption in a certain region is more than 890 kilowatt-hours (kWh). You want to test this claim. You find that a random sample of 62 residential customers has a mean monthly consump