23. The vertical force (Fz) needed to hold the flange in place as shownа.-FAz + P141 – P2A2 cos 30 – (Wn + Ww) = m(VoutCos30 – Vin)b.-FAz + P141 + p2A2 cos 30 – (Wn + Ww) = m(VoutSsin30 – Vin)30C.-FAz + P1A1 – p2A2 sin 30 – (Wn + Ww) = m(VourCos30 – Vin)contralvolumeArea- 0.01 m?d.-FAz + P141 – P2A2 sin 30 – (W, + Ww) = m(VoutSsin30 – Vin)Nozzie(i).PAreo-002 mPA,0.10 ms

Given Fluid is flowing from section 1 to 2 in a control volume Forces acting on the control volume…

23. The vertical force (Fz) needed to hold the flange in place as shown -FAz + P1A1 – p2A2 cos 30 – (W, + Ww) = m(Voutcos30 – Vin) b. а. PA -FAz + P1A1 + p2A2 cos 30 – (W, + Ww) = m(VoutSsin30 – Vin) -FAz + P1A1 – p2A2 sin 30 – (Wn + Ww) = m(VoutCos30 – Vin) d. (2) 30 Contro l volume C. Area-0.01 m -FAz + P1A1 – p2A2 sin 30 – (W, + Ww) = m(Vout Sin30 – Vin) %3D Nozze- Fax p- 40 kE fArea-002 m PA, 0.10 ms

23. The vertical force (Fz) needed to hold the flange in place as shown -FAz + P1A1 – p2A2 cos 30 – (W, + Ww) = m(Voutcos30 – Vin) b. а. PA -FAz + P1A1 + p2A2 cos 30 – (W, + Ww) = m(VoutSsin30 – Vin) -FAz + P1A1 – p2A2 sin 30 – (Wn + Ww) = m(VoutCos30 – Vin) d. (2) 30 Contro l volume C. Area-0.01 m -FAz + P1A1 – p2A2 sin 30 – (W, + Ww) = m(Vout Sin30 – Vin) %3D Nozze- Fax p- 40 kE fArea-002 m PA, 0.10 ms

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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