23. Number of Births The graph of the discrete probabilitydistribution below represents the number of live births by amother 50-54 years old who had a live birth in 2013.Source: National Vital Statistics Report.Number of Live Births,50-to 54-Year-Old Mother0.40.3520.350.30.2620.250.20.150.1240.0960.10.047 0.0540.050.018 0.020 0.016 0.0118 9 105 6 70 12 34Child Number(a) What is the probability that a randomly selected 50- to54-year-old mother who had a live birth in 2013 has had herfourth live birth?(b) What is the probability that a randomly selected 50- to54-year-old mother who had a live birth in 2013 has had herfourth or fifth live birth?(c) What is the probability that a randomly selected 50- to54-year-old mother who had a live birth in 2013 has had hersixth or more live birth?Probability

(a).Here, X denoted the number of 50-to-54-year-old mother who had a live birth in 2013.The…

Answered: 23. Number of Births The graph of the…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The U.S. Coast Guard maintains a database of the number, source, and location of oil spills in the U.S. navigable and territorial waters. The following is a probability distribution for location of oil spill events. [Source: Statistical Abstract of the United States.] Location Probability Atlantic Ocean 0.008 Pacific Ocean 0.037 Gulf of Mexico 0.233 Great Lakes 0.020 Other Lakes 0.002 Rivers and canals 0.366 Bays and sounds 0.146 Harbors 0.161 Other 0.027 If an oil spill is selected at random from the database, what is the probability: The oil spill occurred in an ocean? The oil spill occurred in a lake or harbor? The oil spill did not occur in a lake, ocean, river, or canal?
Also how much do the top 10% of customers spend?
The accompanying data represent the total travel tax (in dollars) for a 3-day business trip in 8 randomly selected cities. A normal probability plot suggests the data could come from a population that is normally distributed. A boxplot indicates there are no outliers. Complete parts (a) through (c) below. 68.09 79.99 70.42 83.11 79.33 85.94 101.02 97.39 O E Click the icon to view the table of critical t-values. (a) Determine a point estimate for the population mean travel tax. A point estimate for the population mean travel tax is $ (Round to two decimal places as needed.) Clear all Check answer Help me solve this View an example Get more help - G Search or type URL esc & # delete 6 8 9 2 3 4 5 P Y U Q W E R tab K S D F G H A caps lock B M >
During a certain week, the mean price of gasoline in the New england region was $3.796 per gallon. A random sample of gas station is selected from this population what is the probability that the mean price for the smoke was between $3.781 and $3.811 that week?
Use the tabulated cumulative normal distribution (Table A.2 or the inside cover of Navidi) to find the missing value in the probability distribution plots shown below. The numbers below the curve are the relevant values of X, and the numbers above the curve represent the shaded area. a. b. 1 0.4 0.3 0.2 0.1- 00 0.4 0.3 0.2 0.1- 0.0 04 0.3 0.2 0.1- 0.0 ??? Distribution Plot Normal, Mean=0, StDev=1 -1.175 0 X Distribution Plot Normal, Mean=0, StDev=1 0 X Distribution Plot Normal, Mean=0, StDev=1 0 ??? 1 ??? 0.025
find mean and sd.. Outcome Probability 1 0.02 2 0.13 3 0.21 4 0.18 5 0.46
Historical data show that customers who download music from a popular Web service spend approximately $24 per month, with a standard deviation of $4. Assume the spending follows the normal probability distribution. Find the probability that a customer will spend at least $20 per month. How much (or more) do the top 7% of customers spend? What is the probability that a customer will spend at least $20 per month?
Create a probability distribution table for your data. Data: 0.20, 0.20, 0.46, 0.46, 2.10, 2.10, 5.50, 11.80, 12.20, 12.20, 13.22, 14.65, 16.07, 17.49, 18.91, 20.33, 20.50, 20.50, 21.75, 23.18
find mean . Outcome Probability 1 0.03 2 0.3 3 0.12 4 0.03 5 0.22 6 0.3
The accompanying data represent the total travel tax (in dollars) for a 3-day business trip in 8 randomly selected cities. A normal probability plot suggests the data could come from a population that is normally distributed. A boxplot indicates there are no outliers. Complete parts (a) through (c) below. 68.09 79.99 70.42 83.11 79.33 85.94 101.02 97.39 O E Click the icon to view the table of critical t-values. (a) Determine point estimate for the population mean travel tax. A point estimate for the population mean travel tax is $ 83.16 (Round to two decimal places as needed.) (b) Construct and interpret a 95% confidence interval for the mean tax paid for a three-day business trip. Select the correct choice below and fill in the answer boxes to complete your choice. (Round to two decimal places as needed.) O A. One can be % confident that the mean travel tax for all cities is between $ and $. O B. There is a % probability that the mean travel tax for all cities is between $ and $. O C.…
Please refer to the lesson and answer the activity
The normal distribution curve can be used as a probability distribution curve for normally distributed variables. Group of answer choices False True

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