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23. lodide ion (1) is the conjugate base of hydroiodic acid (HI). Why doesn't sodium iodide cause an appreciable increase in the pH of water when it dissolves into Na* and I ions? (a) The Na' is acidic and neutralizes the basicity of I. (b) It is a stronger acid than it is a base in water, so Nal actually lowers the pH when dissolved. (c) There are no H₂O* ions present in the solution that could react with I. (d) At least a small amount of HI must be present in order for I to act as a base to raise the pH. (e) HI is a strong acid that reacts completely, which makes I a correspondingly weak base. 24. K, for methylamine (CH₂NH₂) is the equilibrium constant for which reaction? (a) CHÍNH; + HỌ = CHINH + HO* (b) CHÍNH2 + H2O = CHÍNH * + OH (C) CHÍNH, + HO* = CHÍNH * + H2O (d) CH₂NH₂ + OH CH₂NH™ + H₂O (e) None of the above

23. lodide ion (1) is the conjugate base of hydroiodic acid (HI). Why doesn't sodium iodide cause an appreciable increase in the pH of water when it dissolves into Na* and I ions? (a) The Na' is acidic and neutralizes the basicity of I. (b) It is a stronger acid than it is a base in water, so Nal actually lowers the pH when dissolved. (c) There are no H₂O* ions present in the solution that could react with I. (d) At least a small amount of HI must be present in order for I to act as a base to raise the pH. (e) HI is a strong acid that reacts completely, which makes I a correspondingly weak base. 24. K, for methylamine (CH₂NH₂) is the equilibrium constant for which reaction? (a) CHÍNH; + HỌ = CHINH + HO* (b) CHÍNH2 + H2O = CHÍNH * + OH (C) CHÍNH, + HO* = CHÍNH * + H2O (d) CH₂NH₂ + OH CH₂NH™ + H₂O (e) None of the above

Introductory Chemistry: A Foundation
Introductory Chemistry: A Foundation
9th Edition
ISBN:9781337399425
Author:Steven S. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Donald J. DeCoste
Chapter16: Acids And Bases
Section: Chapter Questions
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23. lodide ion (1) is the conjugate base of hydroiodic acid (HI). Why doesn't sodium iodide cause an appreciable increase in the pH of water when it dissolves into Na* and I ions? (a) The Na' is acidic and neutralizes the basicity of I (b) It is a stronger acid than it is a base in water, so Nal actually lowers the pH when dissolved. (c) There are no H₂O* ions present in the solution that could react with I. (d) At least a small amount of HI must be present in order for I to act as a base to raise the pH. (e) HI is a strong acid that reacts completely, which makes I a correspondingly weak base. 24. K, for methylamine (CH3NH₂) is the equilibrium constant for which reaction? (a) CHÍNH, + HO - CHÍNH + HO CH₂NH3 + OH* = CHÍNH + H2O CH₂NH™ + H₂O (b) CH₂NH₂ + H₂O (C) CHÍNH, + HO (d) CH₂NH₂ + OH (e) None of the above
Transcribed Image Text:23. lodide ion (1) is the conjugate base of hydroiodic acid (HI). Why doesn't sodium iodide cause an appreciable increase in the pH of water when it dissolves into Na* and I ions? (a) The Na' is acidic and neutralizes the basicity of I (b) It is a stronger acid than it is a base in water, so Nal actually lowers the pH when dissolved. (c) There are no H₂O* ions present in the solution that could react with I. (d) At least a small amount of HI must be present in order for I to act as a base to raise the pH. (e) HI is a strong acid that reacts completely, which makes I a correspondingly weak base. 24. K, for methylamine (CH3NH₂) is the equilibrium constant for which reaction? (a) CHÍNH, + HO - CHÍNH + HO CH₂NH3 + OH* = CHÍNH + H2O CH₂NH™ + H₂O (b) CH₂NH₂ + H₂O (C) CHÍNH, + HO (d) CH₂NH₂ + OH (e) None of the above
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