23. lodide ion (1) is the conjugate base of hydroiodic acid (HI). Why doesn't sodium iodide cause an appreciable increase in the pH of water when it dissolves into Na* and I ions? (a) The Na' is acidic and neutralizes the basicity of I. (b) It is a stronger acid than it is a base in water, so Nal actually lowers the pH when dissolved. (c) There are no H₂O* ions present in the solution that could react with I. (d) At least a small amount of HI must be present in order for I to act as a base to raise the pH. (e) HI is a strong acid that reacts completely, which makes I a correspondingly weak base. 24. K, for methylamine (CH₂NH₂) is the equilibrium constant for which reaction? (a) CHÍNH; + HỌ = CHINH + HO* (b) CHÍNH2 + H2O = CHÍNH * + OH (C) CHÍNH, + HO* = CHÍNH * + H2O (d) CH₂NH₂ + OH CH₂NH™ + H₂O (e) None of the above

23. lodide ion (1) is the conjugate base of hydroiodic acid (HI). Why doesn't sodium iodide cause an appreciable increase in the pH of water when it dissolves into Na* and I ions? (a) The Na' is acidic and neutralizes the basicity of I. (b) It is a stronger acid than it is a base in water, so Nal actually lowers the pH when dissolved. (c) There are no H₂O* ions present in the solution that could react with I. (d) At least a small amount of HI must be present in order for I to act as a base to raise the pH. (e) HI is a strong acid that reacts completely, which makes I a correspondingly weak base. 24. K, for methylamine (CH₂NH₂) is the equilibrium constant for which reaction? (a) CHÍNH; + HỌ = CHINH + HO* (b) CHÍNH2 + H2O = CHÍNH * + OH (C) CHÍNH, + HO* = CHÍNH * + H2O (d) CH₂NH₂ + OH CH₂NH™ + H₂O (e) None of the above

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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