23. A rocket carrying fireworks is launched from a hill above a lake. The rocket will fall into lake after exploding at its maximum height. The rocket's height above the surface of the lake is given by h(t) = -16t2 + 64t + 80, where h is in feet and t is in seconds. (a) How long will it take for the rocket to hit 128 feet? (b) After how many seconds after it is launched will the rocket hit the lake?

Q: X-2-9x-1+14=0

A: Let z=x^-1We replace x^-2 by z^2 and x^-1 by z.

Q: ove 1(0-0) ×5)| (-2.3.-1) × (5.1.2) X IDI (5.1.2)

A: Given query is to solve indicated vector operation.

Q: What is the answer to: 0.6(4-2x)=20.5-(3x+10) ?

A: we are given that  0.6( 4-2x)=20.5-(3x+10) we first multiply these elements as follows, 0.6×(4)…

Q: (s2 + 2s - 8) ÷ (s + 4)

A:

Q: +

A: We will find x.

Q: X²-6x+13=0

A:

Q: solve for x in the equation "8x - 3 = 5(x - 1) + 3x"

A:

Q: 3x15=17-x

A: The given problem: 3×15=17-x   Solving the above equation is given as: 3×15=17-x45=17-xx=17-45=-28…

Q: Simplify : (y-1 - (y + 5)-1) / 5

A:

Q: Determine: 2s2+10s . С-1 l(s²-2s+5)(s+1))

A:

Q: - Solve: (3x-1)(x²-4) 5x(x−7) 20

A: Given,            3x-1x2-45xx-7≥0

Q: 5Vx+8=20 how to find x=?

A:

Q: a +7b=-52.f(b)=?

A: Given4a+7b=-52

Q: If Q(x) = 6x - 1, find Q(- 7). 2 Q(- 7) =

A: The objective of the question find the the value of the function at x=-7.

Q: What is 300x-(-12,000) When x=2

A: NOTE: Refresh your page if you can't see any equations. . the given expression is

Q: (x+3)4=140

A: The given equation is  (x + 3)4 = 140

Q: a x (3 x 6) = 400

A: a x (3 x 6) = 400 a=?

Q: y=(-32+x)

A: We have to explain the given statement.

Q: x2-x+4=0

A: Given equation is

Q: (4x+2)0 L. 300 (8+6xP

A:

Q: (v) 4¹-r 32x+5

A:

Q: (7x+31) + (21x-19) = 180

A:

Q: X - (-8) = 16 X= ?

A: Given that  X-(-8) =16 Then we have to find value of x.  So now..  X-(-8) =16 X+8=16 X=16-8 X=8

Q: (a + 5) = 49 x +5 2.

A:

Q: Solve : (x+4)3 – 3 =- 2

A:

Q: Differentiate y =(2x-1)(/3x-5

A: The given equation is y=2x-13x-5.

Q: 2(-3x + 10)= -3

A:

Q: Solve:(x + 3)/4 =[(x - 2)/3 +1/4]

A: x+34=x-23+14

Q: Solve: 2/5(3x - 7) + 1 = (x/4) - 2

A: To Solve: 2/5(3x - 7) + 1 = (x/4) - 2 253x - 7  + 1 = x4  - 2 x = ?

Polynomials

Try substituting 1. You will get 6 and not 0. Try other real values also. What About -2? Let us check.