23 Use the picture below (a) b. 45° 4V2 Part A Find the value of a

Elementary Geometry For College Students, 7e
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ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
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23. Find the value of a and the value of b using the picture.
**Question 23/36**

---

**Use the picture below**

*(a)* 

![Right Triangle](image-url-here)

In the given right triangle, we have:

- The length of one leg as \( a \).
- The length of the other leg as \( b \).
- The hypotenuse has a length of \( 4\sqrt{2} \).
- One of the angles is \( 45^\circ \).

---

**Part A**

Find the value of \( a \)

Options:

1. \( \frac{4}{\sqrt{2}} \)
2. \( 4\sqrt{2} \)
3. \( 4 \)
4. \( \frac{4}{2} \)

---

**Explanation:**

The given diagram represents a right triangle with a \( 45^\circ \) angle, making it a 45-45-90 triangle. In such triangles, the legs are congruent, and the hypotenuse is \( \sqrt{2} \) times the length of each leg.

Given the hypotenuse is \( 4\sqrt{2} \), we can set up the following relationship:

\[ a\sqrt{2} = 4\sqrt{2} \]

Solving for \( a \):

\[ a = 4 \]

Therefore, the value of \( a \) is \( 4 \).
Transcribed Image Text:**Question 23/36** --- **Use the picture below** *(a)* ![Right Triangle](image-url-here) In the given right triangle, we have: - The length of one leg as \( a \). - The length of the other leg as \( b \). - The hypotenuse has a length of \( 4\sqrt{2} \). - One of the angles is \( 45^\circ \). --- **Part A** Find the value of \( a \) Options: 1. \( \frac{4}{\sqrt{2}} \) 2. \( 4\sqrt{2} \) 3. \( 4 \) 4. \( \frac{4}{2} \) --- **Explanation:** The given diagram represents a right triangle with a \( 45^\circ \) angle, making it a 45-45-90 triangle. In such triangles, the legs are congruent, and the hypotenuse is \( \sqrt{2} \) times the length of each leg. Given the hypotenuse is \( 4\sqrt{2} \), we can set up the following relationship: \[ a\sqrt{2} = 4\sqrt{2} \] Solving for \( a \): \[ a = 4 \] Therefore, the value of \( a \) is \( 4 \).
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