23) It took 116 hours to produce 603 g of metal X by performing electrolysis on molten XCI3 with a current of 2.00 A. Calculate the molar mass of X. a) 55.8 g/mol b) 72.6 g/mol c) 27.0 g/mol d) 204 g.mol e) 209 g/mol
23) It took 116 hours to produce 603 g of metal X by performing electrolysis on molten XCI3 with a current of 2.00 A. Calculate the molar mass of X. a) 55.8 g/mol b) 72.6 g/mol c) 27.0 g/mol d) 204 g.mol e) 209 g/mol
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Transcribed Image Text:# Standard Reduction Potentials
The following table lists standard reduction potentials (E°) for various redox couples in volts (V). Standard reduction potentials are used to predict the direction of electron flow in electrochemical cells.
## Reduction Potential Table
| Couple | E° (Volts) | Couple | E° (Volts) |
|-----------------|------------|----------------|------------|
| F₂ | HF (H⁺) | +3.03 | SO₄²⁻ | H₂SO₃ (H⁺) | +0.20 |
| F₂ | F⁻ | +2.87 | Sn⁴⁺ | Sn²⁺ | +0.15 |
| S₂O₈²⁻ | SO₄²⁻ | +2.05 | S | H₂S (H⁺) | +0.141 |
| BiO₃⁻ | Bi³⁺ | +2.0 | Hg₂Br₂ | Hg (Br⁻) | +0.140 |
| H₂O₂ | H₂O (H⁺) | +1.78 | AgBr | Ag (Br⁻) | +0.0713 |
| PbO₂ | PbSO₄ (H⁺, SO₄²⁻) | +1.685 | H⁺ | H₂ | +0.0000 |
| Ce⁴⁺ | Ce³⁺ | +1.61 | Pb²⁺ | Pb | -0.126 |
| MnO₄⁻ | Mn²⁺ (H⁺) | +1.491 | Sn²⁺ | Sn | -0.136 |
| ClO₃⁻ | Cl⁻ | +1.47 | AgI | Ag (I⁻) | -0.152 |
| PbO₂ | Pb²⁺ (H⁺) | +1.46 | Ni²⁺ | Ni | -0.250 |
| Au³⁺ | Au | +1.42 | Co²
![**Electrolysis Calculation Example**
**Problem Statement:**
It took 116 hours to produce 603 g of metal X by performing electrolysis on molten XCl₃ with a current of 2.00 A. Calculate the molar mass of X.
**Multiple Choice Answers:**
a) 55.8 g/mol
b) 72.6 g/mol
c) 27.0 g/mol
d) 204 g/mol
e) 209 g/mol
**Solution Explanation:**
To solve this problem, follow these steps:
1. **Calculate Total Charge (Q):**
Using the formula: \( Q = I \times t \)
Where:
- \( I = 2.00 \) A (Current)
- \( t = 116 \) hours \( = 116 \times 3600 \) seconds (time converted to seconds)
\[ Q = 2.00 \, \text{A} \times 116 \times 3600 \, \text{s} \]
\[ Q = 835200 \, \text{Coulombs (C)} \]
2. **Calculate Moles of Electrons:**
Using Faraday's constant (\( F = 96485 \) C/mol)
\[ \text{Moles of electrons} = \frac{Q}{F} \]
\[ \text{Moles of electrons} = \frac{835200 \, \text{C}}{96485 \, \text{C/mol}} \]
\[ \text{Moles of electrons} \approx 8.65 \, \text{mol} \]
3. **Relate Moles of Electrons to Moles of Metal X:**
From the formula XCl₃, each mole of metal X requires 3 moles of electrons (since X has a +3 charge).
\[ \text{Moles of X} = \frac{\text{Moles of electrons}}{3} \]
\[ \text{Moles of X} = \frac{8.65 \, \text{mol}}{3} \]
\[ \text{Moles of X} \approx 2.88 \, \text{mol} \]
4. **Calculate Molar Mass of Metal X:**
\[ \text{](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F5d4e0e1f-a295-43e5-adcc-ec19e6606cd6%2Fe520c050-0ff0-4ebe-9a79-604be246e544%2Ft60yssu.png&w=3840&q=75)
Transcribed Image Text:**Electrolysis Calculation Example**
**Problem Statement:**
It took 116 hours to produce 603 g of metal X by performing electrolysis on molten XCl₃ with a current of 2.00 A. Calculate the molar mass of X.
**Multiple Choice Answers:**
a) 55.8 g/mol
b) 72.6 g/mol
c) 27.0 g/mol
d) 204 g/mol
e) 209 g/mol
**Solution Explanation:**
To solve this problem, follow these steps:
1. **Calculate Total Charge (Q):**
Using the formula: \( Q = I \times t \)
Where:
- \( I = 2.00 \) A (Current)
- \( t = 116 \) hours \( = 116 \times 3600 \) seconds (time converted to seconds)
\[ Q = 2.00 \, \text{A} \times 116 \times 3600 \, \text{s} \]
\[ Q = 835200 \, \text{Coulombs (C)} \]
2. **Calculate Moles of Electrons:**
Using Faraday's constant (\( F = 96485 \) C/mol)
\[ \text{Moles of electrons} = \frac{Q}{F} \]
\[ \text{Moles of electrons} = \frac{835200 \, \text{C}}{96485 \, \text{C/mol}} \]
\[ \text{Moles of electrons} \approx 8.65 \, \text{mol} \]
3. **Relate Moles of Electrons to Moles of Metal X:**
From the formula XCl₃, each mole of metal X requires 3 moles of electrons (since X has a +3 charge).
\[ \text{Moles of X} = \frac{\text{Moles of electrons}}{3} \]
\[ \text{Moles of X} = \frac{8.65 \, \text{mol}}{3} \]
\[ \text{Moles of X} \approx 2.88 \, \text{mol} \]
4. **Calculate Molar Mass of Metal X:**
\[ \text{
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