2=(2>60) (2<80) 5. A The ages of the thousands of residents of a retirement community are normally distributed with a mean of 70 and a standard deviation of 4 years. a. What proportion of this population is between 60 and 80? Z 2=60-70 = -2.5 = 6.21 4 2-80-70 시 2= = 2.5=6.21 71.5-45 4 99274 1-,99379 -3 b. If one sample of 45 residents is chosen at random, what is the probability that the sample mean age will be between 68.5 and 71.75? 68.5-45 2= 5.87 ماما - = 6.21% +6.21= -4 12.24% is between con 600-80 years old 2.5 C. Between which two symmetric limits are 95% of all the possible values of the sample means? a)
2=(2>60) (2<80) 5. A The ages of the thousands of residents of a retirement community are normally distributed with a mean of 70 and a standard deviation of 4 years. a. What proportion of this population is between 60 and 80? Z 2=60-70 = -2.5 = 6.21 4 2-80-70 시 2= = 2.5=6.21 71.5-45 4 99274 1-,99379 -3 b. If one sample of 45 residents is chosen at random, what is the probability that the sample mean age will be between 68.5 and 71.75? 68.5-45 2= 5.87 ماما - = 6.21% +6.21= -4 12.24% is between con 600-80 years old 2.5 C. Between which two symmetric limits are 95% of all the possible values of the sample means? a)
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2=(2>60) (2480)
5. A The ages of the thousands of residents of a retirement community are normally distributed
with a mean of 70 and a standard deviation of 4 years.
a. What proportion of this population is between 60 and 80?
2=60-70
-2.5 = 6.21
4
2-80-76
4
2=
= 2.5=6.21
1.5
2= 68.5-45 - 5.87
니
71.5-45
4
b. If one sample of 45 residents is chosen at random, what is the probability that the
sample mean age will be between 68.5 and 71.75?
Stru
ماما -
1-,99379
6.
= 6.21% +6.21=
-4
12,24%
is between
60-80
years old
2.5
c. Between which two symmetric limits are 95% of all the possible values of the sample
means?
4
FIST
Standar
4. PCX
a) x-
Expert Solution
Step 1
Let X denote the age of a resident of the retirement community. Given that .
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