223.23.223.10910.10.250.1|126.123.23.1223.69.230.250Custom Subnet maskNumber of needed subnetsNumber of needed usable hostsNetwork AddressAddress classDefault subnet maskCustom subnet maskTotal number of subnetsTotal number of host addressesNumber of usable addressesNumber of bits borrowed601,000128.77.0.0Number of needed usable hosts Network AddressAddress classTotal number of subnetsTotal number of host addressesNumber of usable addressesNumber of bits borrowedWhat is the 2nd subnet range?What is the subnet number for the 5th subnet?What is the subnet broadcast address for the 7th subnet?What are the assignable addresses for the 10th6.126.0.0.0 129 22 230.19255.255.255.0Section BPart 1 (Please show working)Binary To Decimal Conversion12800011011| 101010106432| 16| 841 2|1Answers011011111111100001010101Decimal To Binary Conversion1235013820010AddressClass192.14.2.0148.17.9.1193.42.1.1126.8.156.0Circle the network portion of these addressesCircle the host portion of these addresses:209.240.80.78198.125.87.177199.155.77.56223.250.200.222117,89,56.4517.45.222.45126.201.54.231191.41.35.112215.45.45.0192.200.15.0209.240.80.78198.125.87.177Using the IP address and subnet mask shown write out the network address192.149.24.191255.255.255.0150.203.23.19255.255.0.010.10.10.10255.0.0.0186.13.23.110255.255.255.0223.69.230.250255.255.0.0Using the IP address and subnet mask shown write out the host address:222.49.49.11128.23.230.19| 255.255.0.030 10.1010.10.10.10255.0.0.0200.113.123.11255.255.255.0223.169.23.20255.255.0.0Write the correct default subnet mask for each of the following addresses:191.249.234.191

Name: 223.23.223.10910.10.250.1|126.123.23.1223.69.230.250Custom Subnet mas
Uploaded: 2024-03-20T06:51:23.000Z
Channel: Bartleby
Description: 223.23.223.10910.10.250.1|126.123.23.1223.69.230.250Custom Subnet maskNumber of needed subnetsNumber of needed usable hostsNetwork AddressAddress classDefault subnet maskCustom subnet maskTotal number of subnetsTotal number of host addressesNumber o

128.77.0.0 Number of usable subnet = 60 Number of subnet bits = ceil(log 60) = 6 bits. Address…

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Computer Science

223.23.223.109 10.10.250.1 126.123.23.1 223.69.230.250 Custom Subnet mask Number of needed subnets Number of needed usable hosts Network Address Address class Default subnet mask Custom subnet mask Total number of subnets Total number of host addresses Number of usable addresses Number of bits borrowed 60 1,000 128.77.0.0 Number of needed usable hosts Network Address Address class Total number of subnets Total number of host addresses Number of usable addresses Number of bits borrowed What is the 2nd subnet range? What is the subnet number for the 5th subnet? What is the subnet broadcast address for the 7th subnet? What are the assignable addresses for the 10th 126.0.0.0

223.23.223.109 10.10.250.1 126.123.23.1 223.69.230.250 Custom Subnet mask Number of needed subnets Number of needed usable hosts Network Address Address class Default subnet mask Custom subnet mask Total number of subnets Total number of host addresses Number of usable addresses Number of bits borrowed 60 1,000 128.77.0.0 Number of needed usable hosts Network Address Address class Total number of subnets Total number of host addresses Number of usable addresses Number of bits borrowed What is the 2nd subnet range? What is the subnet number for the 5th subnet? What is the subnet broadcast address for the 7th subnet? What are the assignable addresses for the 10th 126.0.0.0

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Question

223.23.223.109
10.10.250.1
|126.123.23.1
223.69.230.250
Custom Subnet mask
Number of needed subnets
Number of needed usable hosts
Network Address
Address class
Default subnet mask
Custom subnet mask
Total number of subnets
Total number of host addresses
Number of usable addresses
Number of bits borrowed
60
1,000
128.77.0.0
Number of needed usable hosts Network Address
Address class
Total number of subnets
Total number of host addresses
Number of usable addresses
Number of bits borrowed
What is the 2nd subnet range?
What is the subnet number for the 5th subnet?
What is the subnet broadcast address for the 7th subnet?
What are the assignable addresses for the 10th
6.
126.0.0.0

129 22 230.19
255.255.255.0
Section B
Part 1 (Please show working)
Binary To Decimal Conversion
128
00011011
| 10101010
64
32
| 16
| 8
4
1 2
|
1
Answers
01101111
11111000
01010101
Decimal To Binary Conversion
123
50
138
200
10
Address
Class
192.14.2.0
148.17.9.1
193.42.1.1
126.8.156.0
Circle the network portion of these addresses
Circle the host portion of these addresses:
209.240.80.78
198.125.87.177
199.155.77.56
223.250.200.222
117,89,56.45
17.45.222.45
126.201.54.231
191.41.35.112
215.45.45.0
192.200.15.0
209.240.80.78
198.125.87.177
Using the IP address and subnet mask shown write out the network address
192.149.24.191
255.255.255.0
150.203.23.19
255.255.0.0
10.10.10.10
255.0.0.0
186.13.23.110
255.255.255.0
223.69.230.250
255.255.0.0
Using the IP address and subnet mask shown write out the host address:
222.49.49.11
128.23.230.19
| 255.255.0.0
30 10.10
10.10.10.10
255.0.0.0
200.113.123.11
255.255.255.0
223.169.23.20
255.255.0.0
Write the correct default subnet mask for each of the following addresses:
191.249.234.191

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