None 22.The content of BH=---- after execution the following code:MOV AL,10101010BROL AL, 02- after execution the following code:23. The content of BH=MOV BH.1010101овNOT BH- after execution the following code:24. The content of BH=-MOV BH,11001010BNOT BH25.The content of BH=-after execution the following code:MOV BH,10111000вNOT BH

22. null in the code: MOV AL,10101010B ROL AL,02 Here ROL is used to rotate the number of bits, 2…

22.The content of BH= after execution the following code: MOV AL,10101010B ROL AL, 02 23.The content of BH=- after execution the following code: MOV BH, 10101010B NOT BH 24. The content of BH= after execution the following code: MOV BH,11001010B NOT BH

22.The content of BH= after execution the following code: MOV AL,10101010B ROL AL, 02 23.The content of BH=- after execution the following code: MOV BH, 10101010B NOT BH 24. The content of BH= after execution the following code: MOV BH,11001010B NOT BH

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Question

None

22.The content of BH=-
--- after execution the following code:
MOV AL,10101010B
ROL AL, 02
- after execution the following code:
23. The content of BH=
MOV BH.1010101ов
NOT BH
- after execution the following code:
24. The content of BH=-
MOV BH,11001010B
NOT BH
25.The content of BH=-
after execution the following code:
MOV BH,10111000в
NOT BH

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