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22. What is the standard form of the equation x2 - 36y2 - 20x + 64 = 0? (x-10)2 a. - y? = 1 c.(x – 10)2 – = 1 y2 - 36 36 (х-9)2 (y+4)2 = 1 (x-9)2 d. 9. b. 4 (y+4)2 - 4

22. What is the standard form of the equation x2 - 36y2 - 20x + 64 = 0? (x-10)2 a. - y? = 1 c.(x – 10)2 – = 1 y2 - 36 36 (х-9)2 (y+4)2 = 1 (x-9)2 d. 9. b. 4 (y+4)2 - 4

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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22. What is the standard form of the equation x2 - 36y? - 20x + 64 = 0? (x-10)2 а. – y² = 1 c.(x – 10)2 –= 1 - 36 36 (x-9)2 b. 4 (y+4)2 = 1 9. d. 9. (x-9)2 (y+4)2 1 %3D 4
Transcribed Image Text:22. What is the standard form of the equation x2 - 36y? - 20x + 64 = 0? (x-10)2 а. – y² = 1 c.(x – 10)2 –= 1 - 36 36 (x-9)2 b. 4 (y+4)2 = 1 9. d. 9. (x-9)2 (y+4)2 1 %3D 4
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