22. What is the standard form of the equation x2 - 36y2 - 20x + 64 = 0? (x-10)2 a. - y? = 1 c.(x – 10)2 – = 1 y2 - 36 36 (х-9)2 (y+4)2 = 1 (x-9)2 d. 9. b. 4 (y+4)2 - 4
22. What is the standard form of the equation x2 - 36y2 - 20x + 64 = 0? (x-10)2 a. - y? = 1 c.(x – 10)2 – = 1 y2 - 36 36 (х-9)2 (y+4)2 = 1 (x-9)2 d. 9. b. 4 (y+4)2 - 4
Calculus: Early Transcendentals
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Author:James Stewart
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Chapter1: Functions And Models
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Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Transcribed Image Text:22. What is the standard form of the equation x2 - 36y? - 20x + 64 = 0?
(x-10)2
а.
– y² = 1
c.(x – 10)2 –= 1
-
36
36
(x-9)2
b.
4
(y+4)2
= 1
9.
d.
9.
(x-9)2
(y+4)2
1
%3D
4
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